Question

Newton's Ring Experiment

a. Newton's rings are formed with reflected light of wavelength 5890x 10-10 m using a plano-convex lens and a plane glass plate with liquid between them. The diameter of the third bright ring is 2 mm. If the radius of curvature of the curved surface of the lens is 90 cm find the refractive index of the liquid.

b. The diameter of the tenth dark ring in a Newton's ring system viewed normally by reflected light of wavelength 5.9x 105 cm is 0.5 cm. Calculate the thickness of air film and the radius of curvature of the lens.

Answer 1

- solution: (a) Wanelength of light, a=589 08 1010m. The diameter of theird, beright way, Dz amm. Radirs es curvature , R = 90cm = 0.9m. As we know, for bright frizes. De wereld - 21am-1) RX here m=3 M e) il = 262 (3) - () RX & LORA (Deurne (Dz dionid un 10 x 0.8 x 589 X 10-10 (2 x 10-3)? un 0.132 is the required refractive index. & Wanelength of light, x = 5.9 x 105 cm = 5.9 x 103 m Diameter of 10th dark ang Dio=o.scm As for druck being thickners at - in s = 100 t = 10 x 50 x 103 29.5 x 103m at 2. also, for deock nung, or Du Du - un R D x R = 10.5x 10-22 4 x 10 x 5.9 X 103 ² un & 11.068 10-10 marl 22.12 tom t

But think you have written wavelength incorrectly it has to be 5.9x10-5 con = 5.9x10-7 m if this is &t then below are the correct calculation unless ignore this. ta ion 5-?*70+ 2.95 X10-6m & R = o.sx 10-22 x x 5.8 x 10-7 = 1.06m

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