To dilute a prepared solution of 0.05 g/L BTB by a factor of 20, how many mL of water would be needed
Ans :
Diluting factor = ( final volume / solute volume)
putting values :
20 = ( V / 1)
V = 20 L
So if the volume of BTB solution is 1 L having the concentration of 0.05 g/L , the amount of water needed :
= 20 L - 1 L
= 19 L water
To dilute a prepared solution of 0.05 g/L BTB by a factor of 20, how many...
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