Question

Build a relay ladder logic for the following: When SSW1 is switched to the closed position...

Build a relay ladder logic for the following:

  1. When SSW1 is switched to the closed position and NO PB 1 is pressed, Indicator lights 1 & 2 (Pilot Light 1 & 2) will turn on.
  2. Indicator Light 1 will stay illuminated (regardless of the position of SSW1 or NO PB 1).
  3. Indicator Light 2 can be momentarily turned off when NO PB 1 is depressed. Indicator Light 2 should return to its illuminated state once NO PB 1 is released.
  4. The Indicator Lights should remain illuminated (regardless of the position of SSW1 or NO PB 1) until NO PB 2 is pressed. Both Indicator Lights will then be de-energized.
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Answer #1

explanation

when ssw1 is closed coil cr1 gets energised which will make no contact cr1 as closed.

when pb1 is pressed coil cr2 cr3 get energised hence contact cr3 will become closed and contact cr2 will become open

when pb2 is pressed coil cr4 will become energised and its contact cr4 will become open

so asper the ladder diagram the given conditions in the question are fullfilled

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