Design and build a sequential circuit in Logisim to count in the following manner: Q(t +...
Design and build a sequential circuit in Logisim to count in the following manner: Q(t + 1) = (Q(t) + 5) MOD 9. That is, your circuit should count 0, 5, 1, 6, 2, 7, 3, 8, 4, and 0 (then it will repeat). To build this circuit, we will be using JK flip flops.
Homework Answers
EXCITATION TABLE OF JK FLIP FLOP
|
PRESENT STATE |
NEXT STATE |
INPUT |
|
|
Q |
Q+ |
J |
K |
|
0 |
0 |
0 |
X |
|
0 |
1 |
1 |
X |
|
1 |
0 |
X |
1 |
|
1 |
1 |
X |
0 |
STATE TABLE OF COUNTER
|
PRESENT STATE |
NEXT STATE |
JK FLIP FLOPs |
|||||||||||||
|
Q3 |
Q2 |
Q1 |
Q0 |
Q3+ |
Q2+ |
Q1+ |
Q0+ |
J3 |
K3 |
J2 |
K2 |
J1 |
K1 |
J0 |
K0 |
|
0 |
0 |
0 |
0 |
0 |
1 |
0 |
1 |
0 |
X |
1 |
X |
0 |
X |
1 |
X |
|
0 |
0 |
0 |
1 |
0 |
1 |
1 |
0 |
0 |
X |
1 |
X |
1 |
X |
X |
1 |
|
0 |
0 |
1 |
0 |
0 |
1 |
1 |
1 |
0 |
X |
1 |
X |
X |
0 |
1 |
X |
|
0 |
0 |
1 |
1 |
1 |
0 |
0 |
0 |
1 |
X |
0 |
X |
X |
1 |
X |
1 |
|
0 |
1 |
0 |
0 |
0 |
0 |
0 |
0 |
0 |
X |
X |
1 |
0 |
X |
0 |
X |
|
0 |
1 |
0 |
1 |
0 |
0 |
0 |
1 |
0 |
X |
X |
1 |
0 |
X |
X |
0 |
|
0 |
1 |
1 |
0 |
0 |
0 |
1 |
0 |
0 |
X |
X |
1 |
X |
0 |
0 |
X |
|
0 |
1 |
1 |
1 |
0 |
0 |
1 |
1 |
0 |
X |
X |
1 |
X |
0 |
X |
0 |
|
1 |
0 |
0 |
0 |
0 |
1 |
0 |
0 |
X |
1 |
1 |
X |
0 |
X |
0 |
X |
|
1 |
0 |
0 |
1 |
X |
X |
X |
X |
X |
X |
X |
X |
X |
X |
X |
X |
|
1 |
0 |
1 |
0 |
X |
X |
X |
X |
X |
X |
X |
X |
X |
X |
X |
X |
|
1 |
0 |
1 |
1 |
X |
X |
X |
X |
X |
X |
X |
X |
X |
X |
X |
X |
|
1 |
1 |
0 |
0 |
X |
X |
X |
X |
X |
X |
X |
X |
X |
X |
X |
X |
|
1 |
1 |
0 |
1 |
X |
X |
X |
X |
X |
X |
X |
X |
X |
X |
X |
X |
|
1 |
1 |
1 |
0 |
X |
X |
X |
X |
X |
X |
X |
X |
X |
X |
X |
X |
|
1 |
1 |
1 |
1 |
X |
X |
X |
X |
X |
X |
X |
X |
X |
X |
X |
X |
SOP expressions for jk flip flops inputs
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