Question

Determine the value of ΔSsurr at 325 K and assume constant pressure.
Express your answer to 3 significant figures in units of kJ mol-1 K-1.

4NH3(g) + 3O2(g) → 2N2(g) + 6H2O(g) ΔrH = -1267 kJ mol-1

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Answer #1

∆Ssurr = -∆H/T

∆Hrxn = -1267 KJ/mol

T = 325 K

∆Ssurr = -(-1267)/325

= 3.90 KJ/mol.K

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