What is ΔHsys for a reaction at 16.2 °C with ΔSsurr = 389 J mol-1 K-1...

Question

Question

What is ΔHsys for a reaction at 16.2 °C with ΔSsurr = 389 J mol-1 K-1 ? Express your answer in kJ mol-1 .

science chemistry

Answer 1

Answer #1

ΔSsurr = 389 J mol-1 K-1

So,

ΔSsys = -ΔSsurr

= -389 J mol-1 K-1

T = 16.2 oC

= (16.2 + 273.1) K

= 289.3 K

Now use:

ΔSsys = ΔHsys / T

-389 J mol-1 K-1 = ΔHsys / 289.3 K

ΔHsys = -112538 J mol-1

ΔHsys = -112.5 KJ mol-1

Answer: -112.5 KJ mol-1

Answer 2

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