Question

In C,

• Write a program that can accept an arbitrary number of command line arguments, e.g.
• program must do the following:
  1. program needs to split each of the arguments into two halves based on the length of a string. Specifically, the first half will be [0, n/2) and the second half will be [n/2] where n is the length of the string and n > 1. For instances, hello is split into two halves: he and llo. Similarly, world! is split into wor and ld! For the case where n = 1 (i.e., the length of the argument is 1, there will be only first half which is the argument itself)
  2. All the arguments split into two halves will be sorted in the lexicographical order.
  3. Finally, all the sorted halves in the previous step will be printed.

Answer 1

`Hey,

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#include <stdio.h>
#include<math.h>
#include<stdlib.h>
#include<string.h>
int main(int argc,char* argv[])
{
int i,l=argc-1;
for(i=1;i<=l;i++)
{
char first[(int)(floor(strlen(argv[i])/2)+1)],last[(int)(ceil(strlen(argv[i])/2)+1)];
int n=strlen(argv[i]);
int j;
for(j=0;j<n/2;j++)
{
first[j]=argv[i][j];
}
first[n/2]='';
  
for(j=n/2;j<n;j++)
{
last[j-n/2]=argv[i][j];
}
last[n-n/2]='';
if(n!=1)
{
if(strcmp(first,last)>0)
{
printf("%s %s ",last,first);
}
else
printf("%s %s ",first,last);
}
else
printf("%s ",argv[i]);
}

return 0;
}

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