Question

IN PYTHON 3: Given a sentence, s, produce a dictionary that tells you the number of times each word occurs in a string. You may assume each word is lowercase, there are no contractions, and each word is separated by a space. Please note, your function must return the created dictionary.

please test that it works with this test :

wordFrequency("was it a car or cat i saw or was it a kangaroo")

Answer 1

def wordFrequency(s):#definition of function

    #empty dictionary

    dict1={}

    list1=list(s.split(" "))#split the s into spaces and append it to the list1

    i=0#initialize i=0

    while(i<=len(list1)-1):#while loop runs from 0 to len(list1)-1

        count=1#initialize count=1 and ele=first element of list and k=i+1

        ele=list1[i]

        k=i+1

        for j in range(k,len(list1)): #loop runs from k to len(list1)

            if ele in dict1:#if ele in dict1 then breaks the loop

                break

            else:

                if(ele==list1[j]):#else calculate it to check how many times it occured

                    count=count+1# inc count

        if ele not in dict1:#if ele not in dict1

            dict1[ele]=count#appends to ele to the dict1

        i=i+1#Increment i

        if(i==len(list1)):#if i=len(list1)

            print(dict1)#print the dictionary