You place a coin with a mass of 0.006 kg 0.0254 meters from the center of...
You place a coin with a mass of 0.006 kg 0.0254 meters from the center of the table. There is friction between the coin and the table (μs = 0.6, μk = 0.4). You turn the turntable on and it spins up slowly to 33.3rpm. Will the coin slide off?
Homework Answers
Coin will slide of the table, if static friction force on coin is lower than the centripetal force on coin.
Centripetal force on coin will by:
F = m*ac = m*w^2*r
w = 33.3 rpm = 33.3*2*pi/60 = 3.4872 rad/sec
r = 0.0254 m
So,
F = 0.006*0.0254*3.4872^2 = 0.00185 N
Now Friction force on coin will be:
Ff = us*Fn = us*m*g
Ff = 0.6*0.006*9.81
Ff = 0.035 N
Since Ff > F, So coin will not start motion, Coin will not slide off the table.
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Given: a mass (50) kg is on the edge of a rough horizontal
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Given: a mass (50) kg is on the edge of a rough horizontal turntable with radius...
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a mass (50) kg is on the edge of a rough horizontal turntable with radius R = 2.00 m
Friction coefficients between the mass and the table are μs = 0.50 and μk = 0.40.
The table starts to rotate (rotate) around the vertical axis of symmetry with a constant angular acceleration α = 0.60 rad / s2.
It has been requested to calculate the labour that has delivered the frictional force from the start to the time t*...
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a mass (50) kg is on the edge of a rough horizontal turntable with radius R = 2.00 m
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The table starts to rotate (rotate) around the vertical axis of symmetry with a constant angular acceleration α = 0.60 rad / s2.
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Given:
a mass (50) kg is on the edge of a rough horizontal turntable
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0.50 and μk = 0.40.
The table starts to rotate (rotate) around the vertical axis of
symmetry with a constant angular acceleration α = 0.60 rad /
s2.
It has been asked to calculate the speed v* on which the mass
just will not shift. We must use a...
Given:
a mass (50) kg is on the edge of a rough horizontal turntable
with radius R = 2.00 m Friction coefficients between the mass and
the table are μs = 0.50 and μk = 0.40. The table starts to rotate
(rotate) around the vertical axis of symmetry with a constant
angular acceleration α = 0.60 rad / s2. It has been
asked to calculate the specific time t* at which the mass just will
not shift. We must use...
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