Question

   Lab/HW 3  

Write a program that reads in the following data, all entered on one line with at least one space separating them:

a) an integer representing a month

b) an integer representing the day of the month

c) an integer representing a year

1. Check that the month is between 1 and 12. If it’s not print an error message.

2. Day cannot be 0 or less nor can it be more than 31 for all months. Print an error message if these conditions occur. If day is in the range of 0 and 31, you will still need to check other conditions as noted below in 4.

3. Year cannot be less than 1. Print an error message if that occurs.

If any one of these three conditions occurs, only one error message should print and no further code should be executed. If everything is good so far, then continue as below:

4. Check that day is correct for the month. Remember the poem

“30 days has September, April, June and November,

All the rest have 31 except February which has 28 but in a leap year has 29”

a. For all months, except February, you can check if the date is valid by the poem above.

i. If the month has more days than allowed, print a message saying month number NN can not have XXX days (e.g., if the input is 6 31 2018 the message should say month 6 cannot have 31 days)

b. If the month is February, you’ll need to check if the year is a leap year and then decide if the date is correct.

Page 97 in the textbook shows code to determine a leap year. A year is a leap year if (1) it’s divisible by 400 OR

(2) the year is divisible by 4 AND not divisible by 100.​

So, if it’s a leap year any day up to and including 29 is valid, otherwise 28 is the largest date in February. If February has too many days, e.g., the input is 2 29 2001, print an error message stating

2001 is not a leap year, Feb can have only 28 days

5. At any point that you determine that a date is valid, print a message in the format

5 18 2017 is a valid date

6. Your code should print only one message if a date is valid.

7. If it’s invalid, print only one error message. It a date has more than one error for example, the input is 6 45 -1234, it doesn’t matter which error you pick first as long as you indicate only one error.

THESE TEST CASES MUST BE INCLUDED IN YOUR OUTPUT:

Enter month, day, year separated by spaces 6 30 2017

6 30 2017 is a valid date

Enter month, day, year separated by spaces 6 31 2017

month 6 can not have more than 30 days

Enter month, day, year separated by spaces -3 12 2019

-3 is not a valid month

Enter month, day, year separated by spaces 2 29 2000

2 29 2000 is a valid date

Enter month, day, year separated by spaces 2 30 2000

month 2 can not have 30 days

Enter month, day, year separated by spaces 2 -12 2019

month 2 can not have -12 days

Enter month, day, year separated by spaces 2 29 2001

2001 is not a leap year, 29 is invalid

Enter month, day, year separated by spaces 6 32 -109

year can not be negative

Enter month, day, year separated by spaces 6 32 2017

month 6 can not have more than 30 days

There are many ways to approach this problem. I recommend coding the input statements and steps 1-3 first and making sure they work properly.

Then move on to step 4.

• If the month is NOT February, then there’s no need to check for a leap year. Just check if the month is Sept, April, June or Nov in which case it should have no more than 30. You already checked that no month has more than 31 in step 2 so there’s no need to check again.

• If the month is February, check if it’s a leap year in which case 29 is the max; not a leap year 28 is the max. At any point in the code, if a date is invalid print a message to that effect and exit the program. If all the tests have passed, then the date is valid. You should test your code for determining a leap year separately to make sure it works before you include it in the full solution.

Thank you!!!

Answer 1

code:

#include<stdio.h>

int leapyear(int year){//leapyear check function
if (year%400 == 0) // Exactly divisible by 400 e.g. 1600, 2000
return 0;
else if (year%100 == 0) // Exactly divisible by 100 and not by 400 e.g. 1900, 2100
return 1;
else if (year%4 == 0) // Exactly divisible by 4 and neither by 100 nor 400 e.g. 2016, 2020
return 0;
else // Not divisible by 4 or 100 or 400 e.g. 2017, 2018, 2019
return 1;
}

int main() {
int day,month,year;//initilization
int month1[12] = {31,28,31,30,31,30,31,31,30,31,30,31};
printf("Enter month, day, year separated by spaces ");
scanf("%d %d %d",&month,&day,&year);//taking input
if(month>12 || month<1){//check valid month
printf("%d is not a valid month",month);
}else if(day<1){//check valid day
printf("month %d can not have %d days",month,day);
}else if(year<1){//check valid year
printf("year can not be negative");
}else{
if(month!=2){//month is not 2
if(day<=month1[month-1]){//check for month have correct no of days
printf("%d %d %d is a valid date",month,day,year);
}else{
printf("month %d can not have more than %d days",month,month1[month-1]);
}
}else{
if(day>29){
printf("month %d can not have %d days",month,day);
}else{
if(leapyear(year)==0){ //check for leap year
printf("%d %d %d is a valid date",month,day,year);
}else if(day<=28){//if not leap year and day <=28
printf("%d %d %d is a valid date",month,day,year);
}else{
printf("%d is not a leap year, 29 is invalid",year);
}
}
}
}
return 0;
}

screenshot with output: