Consider the given functions bellow. Sort all of them using
the
asymptotic order (big-O). Provide short explanation for your
answer.
3 log n
3 log log n
nlog n
5n
nn^(1/4)
(n/4)(n/4)
Hey,
Note: Brother in case of any queries, just comment in box I would be very happy to assist all your queries
3*log(log(n))<log(n)<nlog n <5n<nn^(1/4)<(n/4)(n/4)
As we know n>log(n)
So, taking log on both sides
log(n)>log(log(n))
We know n^x >log(n)
We also know
log(n)<n^(1/4)<n
So, taking powers of n in same order
n^(log(n))<nn^(1/4)<(n/4)(n/4)
Kindly revert for any queries
Thanks.
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