Question

HOW DOES THE CODE WORK AND PLEASE TELL ME WHERE DID THE NUMBER [J] COME FROM WHEN IT HASN'T BEEN DECLARED IN THE ABOVE STATEMENT

MOREOVER KINDLY ALSO DRY RUN THE PROGRAM TO MAKE IT MUCH EASIER TO UNDERSTAND
int main()
{

int i, j, a, n, number[i];
printf("Enter the value of N \n");
scanf("%d", &n);

printf("Enter the numbers \n");
for (i = 0; i < n; i++)
scanf("%d", &number[i]);

for (i = 0; i < n; ++i)
{

for (j = i + 1; j < n; j++)
{

if (number[i] > number[j])
{

a = number[i];
number[i] = number[j];
number[j] = a;

}

}

}

printf("The numbers arranged in ascending order are given below \n");
for (i = 0; i < n; ++i)
printf("%d\n", number[i]);

}

Answer 1

#include<stdio.h>

int main()
{

int i, j, a, n, number[i];
printf("Enter the value of N \n");
scanf("%d", &n);

printf("Enter the numbers \n");
for (i = 0; i < n; i++)
scanf("%d", &number[i]);

for (i = 0; i < n; ++i)
{

for (j = i + 1; j < n; j++)
{

if (number[i] > number[j])
{

a = number[i];
number[i] = number[j];
number[j] = a;

}

}

}

printf("The numbers arranged in ascending order are given below \n");
for (i = 0; i < n; ++i)
printf("%d\n", number[i]);
return 0;
}

In the above code number[j] means the array element at the position j in the array number,where j = i+1

Suppose if i= 0 then j will be 1 (j = 0 + 1)

So,if( number[0] > number[1] ) is checked