Question

Convert the below C code to basic MIPS. The result of this code should ask for two numbers to be inputed and give the answer. For example if 3 and 5 are inputed then the final answer should be as follows: 3&5=1, 3|5=7, 3^5=6, << = 12&20, >> = 0&1, and finally ~ = -4&-6. Please run the code yourself before you upload it to make sure it works. Start the code with .data. Thank you so much.

#include <stdio.h>

int main(void)
{
printf("Insert two numbers\n");
int a,b,c;
scanf("%d",&a);
scanf("%d",&b);
c=a&b;
printf("%d&%d=%d\n",a,b,c);

printf("Insert two numbers\n");
scanf("%d",&a);
scanf("%d",&b);
c=a|b;
printf("%d|%d=%d\n",a,b,c);

printf("Insert two numbers\n");

scanf("%d",&a);
scanf("%d",&b);
c=a^b;
printf("%d^%d=%d\n",a,b,c);

printf("Insert two numbers\n");

scanf("%d",&a);
scanf("%d",&b);
a=a<<2;
b=b<<2;
printf("%d&%d\n",a,b);

printf("Insert two numbers\n");

scanf("%d",&a);
scanf("%d",&b);
a=a>>2;
b=b>>2;
printf("%d&%d\n",a,b);

printf("Insert two numbers\n");
int d;
scanf("%d",&a);
scanf("%d",&b);
c=~a;
d=~b;
printf("~%d=%d\n""~%d=%d\n",a,c,b,d);

return 0;
}

Answer 1

.data
   prompt:    .asciiz    "Insert two numbers\n"
   andsym:    .asciiz    "&"
   orsym: .asciiz    "|"
   xorsym:    .asciiz    "^"
   negsym:    .asciiz    "~"
   eqsym: .asciiz    "="
   newline:.asciiz    "\n"

.text
   # display prompt
   la $a0, prompt
   li $v0, 4
   syscall

   # read a number
   li $v0, 5
   syscall

   # store input(a) in $t0
   move $t0, $v0

   # read another number
   li $v0, 5
   syscall

   # store input(b) in $t1
   move $t1, $v0

   and $t2, $t0, $t1  # c = a & b

   # print a
   move $a0, $t0
   li $v0, 1
   syscall

   # print &
   la $a0, andsym
   li $v0, 4
   syscall

   # print b
   move $a0, $t1
   li $v0, 1
   syscall

   # print =
   la $a0, eqsym
   li $v0, 4
   syscall

   # print c
   move $a0, $t2
   li $v0, 1
   syscall

   # print \n
   la $a0, newline
   li $v0, 4
   syscall

   # display prompt
   la $a0, prompt
   li $v0, 4
   syscall

   # read a number
   li $v0, 5
   syscall

   # store input(a) in $t0
   move $t0, $v0

   # read another number
   li $v0, 5
   syscall

   # store input(b) in $t1
   move $t1, $v0

   or $t2, $t0, $t1   # c = a | b

   # print a
   move $a0, $t0
   li $v0, 1
   syscall

   # print |
   la $a0, orsym
   li $v0, 4
   syscall

   # print b
   move $a0, $t1
   li $v0, 1
   syscall

   # print =
   la $a0, eqsym
   li $v0, 4
   syscall

   # print c
   move $a0, $t2
   li $v0, 1
   syscall

   # print \n
   la $a0, newline
   li $v0, 4
   syscall
   
   # display prompt
   la $a0, prompt
   li $v0, 4
   syscall

   # read a number
   li $v0, 5
   syscall

   # store input(a) in $t0
   move $t0, $v0

   # read another number
   li $v0, 5
   syscall

   # store input(b) in $t1
   move $t1, $v0

   xor $t2, $t0, $t1  # c = a ^ b

   # print a
   move $a0, $t0
   li $v0, 1
   syscall

   # print ^
   la $a0, xorsym
   li $v0, 4
   syscall

   # print b
   move $a0, $t1
   li $v0, 1
   syscall

   # print =
   la $a0, eqsym
   li $v0, 4
   syscall

   # print c
   move $a0, $t2
   li $v0, 1
   syscall

   # print \n
   la $a0, newline
   li $v0, 4
   syscall
   
   # display prompt
   la $a0, prompt
   li $v0, 4
   syscall

   # read a number
   li $v0, 5
   syscall

   # store input in $t0
   move $t0, $v0

   # read another number
   li $v0, 5
   syscall

   # store input in $t1
   move $t1, $v0

   # a = a << 2
   sll $t0, $t0, 2
   # b = b << 2
   sll $t1, $t1, 2

   # print a
   move $a0, $t0
   li $v0, 1
   syscall

   # print &
   la $a0, andsym
   li $v0, 4
   syscall

   # print b
   move $a0, $t1
   li $v0, 1
   syscall

   # print \n
   la $a0, newline
   li $v0, 4
   syscall
   
   # display prompt
   la $a0, prompt
   li $v0, 4
   syscall

   # read a number
   li $v0, 5
   syscall

   # store input in $t0
   move $t0, $v0

   # read another number
   li $v0, 5
   syscall

   # store input in $t1
   move $t1, $v0

   # a = a >> 2
   srl $t0, $t0, 2
   # b = b >> 2
   srl $t1, $t1, 2

   # print a
   move $a0, $t0
   li $v0, 1
   syscall

   # print &
   la $a0, andsym
   li $v0, 4
   syscall

   # print b
   move $a0, $t1
   li $v0, 1
   syscall

   # print \n
   la $a0, newline
   li $v0, 4
   syscall
   
   # display prompt
   la $a0, prompt
   li $v0, 4
   syscall

   # read a number
   li $v0, 5
   syscall

   # store input(a) in $t0
   move $t0, $v0

   # read another number
   li $v0, 5
   syscall

   # store input(b) in $t1
   move $t1, $v0

   nor $t2, $t0, $t0  # c = ~a
   nor $t3, $t1, $t1  # d = ~b

   # print ~
   la $a0, negsym
   li $v0, 4
   syscall

   # print a
   move $a0, $t0
   li $v0, 1
   syscall

   # print =
   la $a0, eqsym
   li $v0, 4
   syscall

   # print c
   move $a0, $t2
   li $v0, 1
   syscall

   # print \n
   la $a0, newline
   li $v0, 4
   syscall

   # print ~
   la $a0, negsym
   li $v0, 4
   syscall

   # print b
   move $a0, $t1
   li $v0, 1
   syscall

   # print =
   la $a0, eqsym
   li $v0, 4
   syscall

   # print d
   move $a0, $t3
   li $v0, 1
   syscall

   # print \n
   la $a0, newline
   li $v0, 4
   syscall