Question

Convert the below C code to basic MIPS. The result of this code should be a^b of the two numbers that you input. For example if you input the numbers 3 and 5 you should get a result of 3^5=6

#include

int main(void)
{
printf("Insert two numbers\n");
int a,b,c;
scanf("%d",&a);
scanf("%d",&b);
c=a^b;
printf("%d^%d=%d\n",a,b,c);
return 0;
}

Answer 1

.data
   prompt:    .asciiz    "Insert two numbers\n"
   xorsym:    .asciiz    "^"
   eqsym: .asciiz    "="
   newline:.asciiz    "\n"

.text
   # display prompt
   la $a0, prompt
   li $v0, 4
   syscall

   # read a number
   li $v0, 5
   syscall

   # store input(a) in $t0
   move $t0, $v0

   # read another number
   li $v0, 5
   syscall

   # store input(b) in $t1
   move $t1, $v0

   xor $t2, $t0, $t1  # c = a ^ b

   # print a
   move $a0, $t0
   li $v0, 1
   syscall

   # print ^
   la $a0, xorsym
   li $v0, 4
   syscall

   # print b
   move $a0, $t1
   li $v0, 1
   syscall

   # print =
   la $a0, eqsym
   li $v0, 4
   syscall

   # print c
   move $a0, $t2
   li $v0, 1
   syscall

   # print \n
   la $a0, newline
   li $v0, 4
   syscall