Give high level pseudocode for someFunction below:
int someFunction(std::string lastName, const Data* array, int
size) {
return binaryFindLastByLastName(lastName, array,
size) - binaryFindFirstByLastName(lastName, array, size) + 1;
}
// Thanks!
Pseudocode:
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High level pseudocode:
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High level pseudocode for someFunction:
This program calculates the difference between the binary of last element of an array and the binary of first element of an array and increments its result by 1.
function someFunction(Argument one, Argument two, Argument three){
return the sum of 1 and difference between binary of last element of Argument two using
Argument one and binary of first element of Argument two using Argument one
end
}
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Give high level pseudocode for someFunction below: int someFunction(std::string lastName, const Data* array, int size) {...
Need help with these array problems. int countAllPunctuation( const string array[ ], int n ); Return the total number of punctuation symbols found in all the elements of the passed array argument. For the purpose of this function, the characters '.' , ',', '!', ';', ''', '-', '/', ':', '?', '"' count as punctuation symbols (that is, period, comma, exclamation mark, semicolon, apostrophe, dash, slash, colon, question mark, and double quote). Return -1 if n <= 0. For example, for...
C++ Need the step count for this function. int binarySearch(const int array[], int size, int value) { int first = 0, last = size − 1, middle, position = −1; bool found = false; while (!found && first <= last) { middle = (first + last) / 2; if (array[middle] == value) { found = true; position = middle; } else if (array[middle] > value) last = middle − 1; else first = middle + 1; } return position; }
One dimensional array What this code print #include <iostream> using namespace std; int main () { const int SIZE = 7; int numbers [SIZE] = {1, 2, 4, 8): // Initialize first 4 elements cout << Here are the contents of the array:\n"; for (int index = 0; index < SIZE: index++} cout << numbers[index] << ; cout << endl; return 0; }
Can you make this a function? Thank you.
int locationOfMin(const string a[], int n): Return the position of a string in the array such that that string is < = every string in the array. If there is more than one such string, return the smallest position of such a string. Return -1 if the array has no elements. Here's an example: string people[5] = { "samwell", "jon", "margaery", "daenerys" "tyrion" }: int j = locationOfMin(people, 5);//returns 3, since daenerys...
How do I do this? -> string print() const; Function to output the data, return the output in the form of string, with all elements in the hash table included and each seperated by a space this is my code: template <class elemType> string hashT<elemType>::print() const { for (int i = 0; i < HTSize; i++){ if (indexStatusList[i] == 1){ cout <<HTable[i]<< " " << endl; } } } **********Rest of the code...
#include <iostream> #include <fstream> using namespace std; //constants const int CAP = 100; //function prototypes bool openFile(ifstream &); void readData(ifstream &, int [], int &); void printData(const int [], int); void sum(const int[], int); void removeItem(int[], int &, int); int main() { ifstream inFile; int list[CAP], size = 0; if (!openFile(inFile)) { cout << "Program terminating!! File not found!" << endl; return -1; } //read the data from the file readData(inFile, list, size); inFile.close(); cout << "Data in file:" <<...
#include <iostream> #include <string> using std::string; using std::cout; using std::endl; void testAnswer(string testname, int answer, int expected) { if (answer == expected) cout << "PASSED: " << testname << " expected and returned " << answer << "\n"; else cout << "FAILED: " << testname << " returned " << answer << " but expected " << expected << "\n"; } // Implement printArray here void printArray(int array[],int b) { for(int i = 0; i<b;i++) { std::cout<< array[i] << "...
#include <iostream>
#include <array>
using namespace std;
int specific_pattern(short pattern[], int size) {
int pattern_found = -1;
for (int i = 0; i < size; i++) {
for (int j = i; j < size; j++)
{
if ((pattern[j]
- pattern[i]) == 20) {
for (int k = j; k < size; k++) {
if ((pattern[k] - pattern[j])
== 20) {
return
i;
}
}
}
}
}
return pattern_found;
}
int main() {
short data[] = { 10,20,31,40,55,60,65525 };
...
howthe output of the following 4 program segments (a) const int SIZE=8; int values[SIZE] = {10, 10, 14, 16, 6, 25, 5, 8}; int index; index=0; res = values[index]; for (int j=1; j<SIZE; j++) { if (values[j] > res) { res = values[j]; index = j; cout << index << res << endl; } } cout <<...
#include <iostream> using namespace std; const int SIZE = 10; void displayGreaterThan(int[], int); void displaySmallerThan(int[],int); void displayArrayContent(int[]); void displayLargestValue(int[]); void displaySmallestValue(int[]); int main(){ int number; int numbers[SIZE] = {9,1,90,98,53,22,76,29,37,65}; cout <<"Enter a number: "; cin >> number; cout << endl; displayGreaterThan(numbers,number); cout << endl; displaySmallerThan(numbers,number); cout << endl; displayArrayContent(numbers); cout << endl; displayLargestValue(numbers); cout << endl; displaySmallestValue(numbers); cout << endl; return 0; } void displayGreaterThan(int value[],int num){ cout << " All larger value(s)than" <<...