Question

Brute force algorithm in C that counts the NUMBER OF TIMES (not just once) a string occurs in a file of text. Text is stored in a file called "data_5.txt"

Answer 1

CODE:

#include<stdio.h>
#include<stdlib.h>
int main()
{ //declaring the file pointer to read the file.
//We use "r" to open the file in read mode.
FILE *f1=fopen("data_5.txt","r");
//declaring the string to check.
char string[200];
//declaring the count that is the no of occurrences of the string.
int count=0;
//declaring a buffer to read the strings from the file text.
char buffer[200];
printf("Enter the string to find its no of occurrences : ");
/*we "%[^\n]" to read a string completely with the spaces
until there is a new line.*/
scanf("%[^\n]",string);
/*We use f scanf to read the text line by line.
"%[^\n] "the space after the specifier will allow you to skip the newline character.
so that we will get only the string escaping all the new lines.
fscanf returns EOF if it is the end of the file.
And we break the loop if it is the end.
*/
while(fscanf(f1,"%[^\n] ",buffer)!=EOF) {
/*we use strcmp to compare two strings.
It returns 0 if they are equal.
*/
if(strcmp(buffer,string)==0)
//We increase count if both are equal
count++;
}
printf("\nThe no of occurrences of the string %s in file data_5.txt is %d\n",string,count);
fclose(f1);//We close the file.
}
CODE ATTACHMENTS:

FILE DIRECTORY:

data_5.txt:

OUTPUT:

We use f scanf to read the text line by line.
We use "%[^\n] "the space after the specifier will allow you to skip the newline character.
so that we will get only the string escaping all the new lines.
fscanf returns EOF if it is the end of the file.
And we break the loop if it is the end.
we use strcmp to compare two strings.
It returns 0 if they are equal.
We then count the occurrences.

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