Knowing the enthalpy of formation of calcium fluoride is -1228 KJ / mol, the enthalpy of the sublimation of calcium is 168kj/mole, the bond enthalpy of fluorine is 155kj/mole, the electron affinity of fluorine is -328 kj/mole, the first ionization enthalpy of calcium is 590kj/mole and the second ionization enthaply is 1145kj/mole, calculate the lattice enthalpy of calcium fluoride.
Knowing the enthalpy of formation of calcium fluoride is -1228 KJ / mol, the enthalpy of...
Given the following information, calculate the lattice energy of CaF2 The enthalpy of formation of CaF2 -1228 kJ/mol Heat of sublimation of Ca 177.8 kJ/mol Bond dissociation energy of F2 159 kJ/mol First ionization energy of Ca 589.8 kJ/mol Second ionization energy of Ca 1145.4 kJ/mol . Electron affinity of F -328 kJ/mot [ Answer : -2644 KJİ I
4) Calculate the lattice enthalpy for calcium fluoride using the Born-Haber cycle method, using the provided table. (Show all your work; 2 points) Enthalpies, AH/(kJ mol) +192 Process Sublimation of Ca(s) Ionization of Ca(g) Dissociation of F2(g) Electron gain by F(g) Formation of CaF (s) +1735 to Ca(ag +157 -328 -1220
The enthalpy of formation of MX is ΔHf° = –527 kJ/mol. The enthalpy of sublimation of M is ΔHsub = 139 kJ/mol. The ionization energy of M is IE = 475 kJ/mol. The electron affinity of X is ΔHEA = –309 kJ/mol. (Refer to the hint). The bond energy of X2 is BE = 223 kJ/mol.
____________________________ Sublimation of Cu: 55 kJ/mol First Ionization Energy of Cu: 840 kJ/mol Sublimation of Au: 43 kJ/mol Second Ionization Energy of Cu: 1240 kJ/mol Bond Dissociation of Cl2: 244 kJ/mol First Ionization Energy of Au: 940 kJ/mol Electron Affinity of Cl2: -349 kJ/mol Second Ionization Energy of Au: 1790 kJ/mol Lattice Energy of AuCl: -1455 kJ/mol Lattice Energy of CuCl: -997 kJ/mol Lattice Energy of AuCl2: -3055 kJ/mol Lattice Energy of CuCl2: -2008 kJ/mol Use the above data to...
Consider the following information. The lattice energy of NaCl is ΔH lattice=−788 kJ/mol The enthalpy of sublimation of Na is ΔHsub=107.5 kJ/mol The first ionization energy of Na is IE1=496 kJ/mol. The electron affinity of Cl is ΔHEA=−349 kJ/mol. The bond energy of Cl2 is BE=243 kJ/mol. Determine the enthalpy of formation, ΔHf, for NaCl(s). ΔHf= kJ/mol
Calculate the enthalpies of formation, ΔHfo, of the following
group 1 fluoride compounds from their elements using the Born–Haber
cycle.
NaF RbF Number Number kJ ol kJ mol AHO, kJ/mol Sublimation of Na(s) 108 86 Sublimation of Rb(s) 158 Dissociation of F2(g Ionization energy of Na(g) 496 ionization energy of Rb(g) 403 Electron affinity of F(g) -322 Lattice enthalpy of NaF(s) 926 Lattice enthalpy of RbF(s) 789
Calculate the lattice energy for LiF(s) given the following: sublimation energy for Li(s) = +166 KJ/mol delta Hf for F(g) = +77 KJ/mol first ionization energy of Li(g) = +520 KJ/mol electron affinity of F(g) = -328 KJ/mol enthalpy of formation of LiF(s) = -617 KJ/mol
Write down the chemical equation for the 2nd ionization (IE2)
energy for calcium. Follow the instructions below:
Calculate IE2 for calcium using the data listed below. For each data item, write down the chemical equation associated with the process (i.e., that defines the process) - making sure to indicate all phases. In order to show your work, demonstrate, using Hess' law, how you came up with the Born-Haber cycle that lead to the net chemical equation for the IE2 of...
Calculate the lattice energy of CaBr2. The standard heat of formation of CaBr2 is -675 kJ/mol. The first ionization energy of Ca is 590 kJ/mol and its second ionization energy is 1145 kJ/mol. The heat of sublimation of Ca[Ca(s)→Ca(g)] is 178 kJ/mol. The bond energy of Br2 is 193 kJ/mol, the heat of vaporization of Br2(l) is 31 kJ/mol, and the electron affinity of Br is -325 kJ/mol.
Consider the following information. The lattice energy of LiCl is ΔH lattice = −834 kJ/mol. The enthalpy of sublimation of Li is ΔH sub = 159.3 kJ/mol. The first ionization energy of Li is IE 1 = 520 kJ/mol. The electron affinity of Cl is ΔH EA = -349 kJ/mol. The bond energy of Cl2 is BE = 243 kJ/mol. Determine the enthalpy of formation, ΔHf, for LiCl(s).