Question

Assume that speeding up the floating-point operations causes a slow down in the data cache accesses. For example, given the additional space taken by the more sophisticated floating-point unit, memory operations take some extra cycles to get to the cache. Specifically, assume that data cache accesses, which consume 10% of the original program execution time, are now slowed down by a factor 1.5×. What is the overall speedup? [

Answer 1

Time taken by data cache access before optimizations = 0.1 x Execution Time of the program

Time taken by data cache access after optimizations = 1.5 x 0.1 x Execution Time of the program