Question

Please do in C and only use stdio.h. Write a program that reads n integers into an array, then prints on a separate line the value of each distinct element along with the number of times it occurs. The values should be printed in ascending order. Turn in your code and input/result together. Suppose, for example, that you input the values -7 3 3 -7 5 5 3 as the elements of your array.

Then your program should print

-7 occurs 2 times

3 occurs 3 times

5 occurs 2 times

Answer 1

Here is code:

#include <stdio.h>

#include <stdlib.h>

int *addElement(int *array, int num, int size)

{

// I need the function please

int *new_arr = (int *)malloc(sizeof(int) * size);

int i;

for (i = 0; i < size - 1; i++)

{

new_arr[i] = array[i];

}

new_arr[i] = num;

return new_arr;

}

// Driver function

int main()

{

int size = 0, num;

int *array;

printf("Enter numbers (0 to quit) : ");

while (1)

{

scanf("%d", &num);

if (num == 0)

break;

array = addElement(array, num, ++size);

}

int dupArray[size], freq[size];

int dupSize = 0;

for (int i = 0; i < size; i++)

{

int found = 0;

for (int j = 0; j < dupSize; j++)

{

if (dupArray[j] == array[i])

{

freq[j] = freq[j] + 1;

found = 1;

break;

}

}

if (found == 0)

{

dupArray[dupSize] = array[i];

freq[dupSize] = 1;

dupSize++;

}

}

for (int i = 0; i < dupSize; i++)

{

printf("%d occurs %d times\n", dupArray[i], freq[i]);

}

}

Output: