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A compound microscope has the objective and eyepiece mounted in a tube that is 18.8 cm long. The focal length of the eyepiece is 2.55 cm , and the near-point distance of the person using the microscope is 24.0 cm . If the person can view the image produced by the microscope with a completely relaxed eye, and the magnification is -4516, what is the distance between the objective lens and the object to be examined? |
by L we will get v and by using magnification formula we will get u
L= 18.8 cm
fe = 2.55 cm
magnification m =-4516
Then object distance is 0.00338 cm (Answer)

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