Question

how to add the digits of the doubled values and the digits that were not doubled from the original number in python?

The first part prints it in a list:

def toDigits(g):
return [int (y) for y in str(g)]
print (str(toDigits(759283)))

The second part: prints every number and multiplies all by 2

def doubleEveryOther(g):
return [int(y) * 2 if i % 2 == 0 else int(y) for i, y in enumerate(toDigits(g))]
print(str(doubleEveryOther(759283)))

The third part: I'm trying to add the digits of the doubled values and the digits that were not doubled from the original number. Example: [14,5,18,2,16,3] becomes 14+5+18+2+16+3 = 58

def sumDigits(g):
return [int (y) sum(doubleEveryOther)]
print(str(sumDigits(759283)))

Answer 1

def toDigits(g):
    return [int(y) for y in str(g)]


print(str(toDigits(759283)))


def doubleEveryOther(g):
    return [int(y) * 2 if i % 2 == 0 else int(y) for i, y in enumerate(toDigits(g))]


print(str(doubleEveryOther(759283)))


def sumDigits(g):
    return sum(doubleEveryOther(g))


print(str(sumDigits(759283)))