Question

Write a Python script named assignment2.py that implements the following steps given an integer value:

1.) Double the value of every second digit beginning from the right. For example, the number 1386 has digits [1, 3, 8, 6] which become [2, 3, 16, 6].

2.) Add the digits of the doubled values and the digits that were not doubled from the original number. For example, [2, 3, 16, 6] becomes 2 + 3 + 1 + 6 + 6 = 18.

3. Calculate the remainder when the sum is divided by 10. For the previous example, the remainder is 8. If the result equals zero then return True otherwise return false.

You must define the following functions for this assignment:

• toDigits takes an integer an returns a list of its digits

• doubleEveryOther takes a list of digits and returns a new list of digits where every other number is doubled beginning from the right.

• sumDigits takes a list of integers and sums up the digits of the numbers.

• validate that indicates whether an integer is valid according to the algorithm described above. This function must use the functions defined previously in this list.

* Note it must be done using python 3 and not import any libraries, functions names must be in there so toDigits is one list doubleEveryOther another list

Answer 1

#give it a thumbs up

Code

def toDigits(x):
   l = []             #empty list
   while x!=0:            #extract digits using while loop
       temp = x%10
       l.append(temp)
       x = int(x/10)
   i = len(l)-1
   rev = []
   while i>=0:           #reverse digits to get them back in correct order
       rev.append(l[i])
       i-=1
   return rev

def doubleEveryOther(x):
   alt = []      
   i = len(x) - 1
   j = 0
   while i>=0:       #from end reverse every second number on list and make new list
       if j%2!=0:
           alt.append(2*x[i])
       else:
           alt.append(x[i])
       i-=1
       j+=1
   i = len(alt)-1
   rev = []
   while i>=0:        #reverse digits to get them back in correct order
       rev.append(alt[i])
       i-=1
   return rev

def sumDigits(x):
   i = 0
   tot = 0
   while i<len(x):    #add digits
       if x[i]/10 == 0:   #if single digit number add directly
           tot += x[i]
       else:           #if 2 or more digit number, split digits and add
           temp = x[i]
           while temp != 0:
               tot += (temp%10)
               temp = int(temp/10)
       i += 1
   if tot%10 == 0:    #if number divisible by 10, return true otherwise false
       return True
   else:
       return False

inp = int(input("Enter number : "))    #input number

li = toDigits(inp)           #first function call

alt = doubleEveryOther(li)       #second function call

tot = sumDigits(alt)           #third function call

print(li)
print(alt)
print(tot)

Output 1

Output 2

Check indentation of the code here if it doesn't work