Enter your answer in the provided box.
What is the pH of 0.85 M pyridinium chloride,
C_{5}H_{5}NHCl?
pKb of C5H5N = 8.77
C5H5NHCl is the salt of strong acid and weak base . so pH < 7
pH = 7 - 1/2 (pKb + log C)
= 7 - 1/2 (8.77 + log 0.85)
pH = 2.65
Note : i took pKb value as 8.77 . please check once whether it is match with your value or not . if any doubt please ask me in comment
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