Solution Preparation
You need to prepare solutions for the reactions you will perform in
the laboratory experiment. You will be given a 0.02M stock solution
of KMnO_{4} and a 0.5M stock solution of
H_{2}C_{2}O_{4}. The total volume of the
solutions should always be 30 mL. You will use DI water to complete
the volume as needed. Complete the table below and copy the
results into your lab notebook for use during the
lab:
Run | Volume KMnO_{4} (mL) | Volume H_{2}C_{2}O_{4} (mL) | [KMnO_{4}] (M) | [H_{2}C_{2}O_{4}] (M) | Water Volume (mL) |
1 | 8.4 | 16.8 | |||
1 | 4.2 | 16.8 | |||
1 | 8.4 | 8.4 |
Molarity (M) = moles/liter; it changes upon dilution and mixing with other solutions as they are sources of additional dilution.
Total volume = 30 mL = 0.03 L
initial moles KMnO4 = 8.4 mL x 10^{-3} L x 0.02M = 0.000168 mol ------------ Run 1 & 3
initial moles KMnO4 = 4.2 mL x 10^{-3} L x 0.02M = 0.000084 mol ------------- Run 2
initial moles H_{2}C_{2}O_{4} = 8.4 mL x 10^{-3} L x 0.5M = 0.0042 mol ------------ Run 3
initial moles H_{2}C_{2}O_{4} = 16.8 mL x 10^{-3} L x 0.5M = 0.0084 mol ----------- Run 1 & 2
Run 1:
water volume = 30 - [8.4 - 16. 8] = 4.8 mL
[KMnO_{4}] (M) = 0.000168 mol / 0.03 L = 0.0056 M
[H_{2}C_{2}O_{4}] (M = 0.0084 mol / 0.03 L = 0.28 M
Run 2:
water volume = 30 - [4.2 - 16. 8] = 9.0 mL
[KMnO_{4}] (M) = 0.000084 mol / 0.03 L = 0.0028 M
[H_{2}C_{2}O_{4}] (M = 0.0084 mol / 0.03 L = 0.28 M
Run 3:
water volume = 30 - [8.4 - 8.4] = 13.2 mL
[KMnO_{4}] (M) = 0.000168 mol / 0.03 L = 0.0056 M
[H_{2}C_{2}O_{4}] (M = 0.0042 mol / 0.03 L = 0.14 M
Run | Volume KMnO_{4} (mL) | Volume H_{2}C_{2}O_{4} (mL) | [KMnO_{4}] (M) | [H_{2}C_{2}O_{4}] (M) | Water Volume (mL) |
1 | 8.4 | 16.8 | 0.0056 | 0.28 | 4.8 |
2 | 4.2 | 16.8 | 0.0028 | 0.28 | 9.0 |
3 | 8.4 | 8.4 | 0.0056 | 0.14 | 13.2 |
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