Consider the following tasks, times, and predecessors for an assembly of set top cable converter boxes:
| TASK ELEMENT | TIME (MINUTES) |
ELEMENT PREDECESSOR |
| A | 3 | — |
| B | 3 | A |
| C | 2 | B |
| D | 2 | B |
| E | 1 | C, D |
| F | 1 | A |
| G | 3 | F |
| H | 3 | G |
| I | 1 | E, H |
Given a cycle time of six minutes, what is the efficiency of your layout? Use the longest task time as primary criterion with largest number of following tasks as secondary criterion.
The assignment of tasks in the stations as per the LPT rule is as follows:
| Station | Remaining time | Eligibles | Was Fit | Assigned time | Remaining time | Idle time |
| I | 6 | A | A | 3 | 3 | 0 |
| 3 | B, F | B | 3 | 0 | ||
| 0 | C, D, F | - | - | 0 | ||
| II | 6 | C, D, F | C | 2 | 4 | 0 |
| 4 | D, F | D | 2 | 2 | ||
| 2 | E, F | F | 1 | 1 | ||
| 1 | E, G | E | 1 | 0 | ||
| 0 | G | - | - | 0 | ||
| III | 6 | G | G | 3 | 3 | 0 |
| 3 | H | H | 3 | 0 | ||
| 0 | I | - | - | 0 | ||
| IV | 6 | I | I | 1 | 5 | 5 |
Efficiency = Sum of task times / (No. of stations * Cycle time)
= 19 / (4*6)
= 0.7917 or 79.17%
Consider the following tasks, times, and predecessors for an assembly of set top cable converter boxes:...
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