Here's the code:
#include<bits/stdc++.h>
using namespace std;
char *binary(long n, char *b) {
int curr_idx = 63;
while(n){
if(n%2 == 0){
b[curr_idx] = '0';
}
else{
b[curr_idx] = '1';
}
n = n/2;
curr_idx--;
}
return b;
}
int main(int argc, char * argv[]){
long n = atol(argv[1]);
char b[65];
// fill with 0's initially
for(int i = 0; i < 65; i++){
b[i] = '0';
}
b[64] = '\0'; // last null terminator
printf("%s\n", binary(n, b));
}
Hello, I have done the question and it is working perfectly fine. I have tried to name the variables in a proper manner to give you a better understanding for the code. I am also attaching the sample input/output file as well. It took me a lot of time to answer this. Please give me an upvote.
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
char* long_to_binary(unsigned long k)
{
static char c[65];
c[0] = '\0';
unsigned long val;
for (val = 1UL << (sizeof(long)*8-1); val > 0; val
>>= 1)
{
strcat(c, ((k & val) == val) ? "1" : "0");
}
return c;
}
int main(int argc, char *argv[]){
if(argc<=1){
printf("usage: binary n");
return 0;
}
long number = atol(argv[1]);
//We cannot use a signed long to calculate the binary values so we
have to typecast the value.
printf("%s\n",long_to_binary((unsigned long)number));
}
Sample input/output file:-

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