If the codon were 5 bases long instead of three, how many codons would exist in a genetic code comprised of only A, T, G, and C?
If the codon was 5 bases long,
Than at each position of codon, 1 out of 4 bases will come.
Probability of a base at any position of codon = 1/4
There are 5 such positions.
Total probability of 5 bases long codon = 1/4 × 1/4 × 1/4 × 1/4 × 1/4 = (1/4)^5 = 1/1024
Total codons = 1/probability of codon
Number of codons = 1024
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If the codon were 5 bases long instead of three, how many codons would exist in...
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