The t value for a 98% confidence interval estimation with 24 degrees of freedom (not the...

Question

Question

The t value for a 98% confidence interval estimation with 24 degrees of freedom
(not the sample size n) is

math Statistics-And-Probability

Answer 1

Answer #1

Solution :

Given that,

Degrees of freedom = df =24

At 98% confidence level the t is ,

= 1 - 98% = 1 - 0.98 = 0.02

/ 2 = 0.02 / 2 = 0.01

t /2,df = t0.01,24 = 2.492159

t value = 2.492159

Answer 2

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