Calculate the Ecell value at 298 K for the cell based on the reaction:
Cu(s) + 2Ag+(aq) ----> Cu+2 (aq) + 2Ag(s)
where [Ag+] = 0.00275 M and [Cu2+] = 8.75×10-4 M.
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Calculate the Ecell value at 298 K for the cell based on the reaction: Cu(s) +...
Calculate the Ecell value at 298 K for the cell based on the reaction: Cu(s) + 2Ag+(aq) ----> Cu+2 (aq) + 2Ag(s) where [Ag+] = 0.00275 M and [Cu2+] = 8.75×10-4 M.
Calculate the Ecell value at 298 K for the cell based on the reaction: Cu(s) + 2Ag+ (aq) → Cu2+ (aq) + 2Ag(s) where [Ag+] = 0.00350 M and [Cu2+] = 7.00x10-4 M. The standard reduction potentials are shown below: Ag+(aq) +e → Ag(s) E° = 0.7996 V Cu2+ (aq) + 2e -→ Cu(s) E° = 0.3419 V 2nd attempt Ecell = V
1. Calculate Ecell at 298 K for a cell involving Sn and Cu and their ions: Sn(s) I Sn2+(aq,.25 m) II Cu2+(aq,.10 m) I Cu(s) a. .47 V b. .49 V c. .50 V Please explain and use equation. Thank you
Calculate Ecell at 298 K for a cell involving Sn and Cu and their ions: Sn(s) I Sn2+(aq, 0.25M) II Cu2=(aq, 0.10M) I Cu(s) A) 0.47 V B) 0.49 V C) 0.50 V
Calculate the E°cell for the following reaction: Cu2+ (aq) + Ni (s) → Cu (s) + Ni2+ (aq) A) (-0.59 ± 0.01) V B) (-0.09 ± 0.01) V C) (0.59 ± 0.01) V D) (0.09 ± 0.01) V --------------------------------------------------------------------------------------------------------- What is the proper line notation for the following reaction? Cu (s) + 2Ag+ (aq) → Cu2+ (aq) + 2Ag (s) A) Cu2+ | Cu || Ag | Ag+ B) Ag+ | Ag || Cu | Cu2+ C) Cu |...
Calculate the E°cell for the following reaction: Cu2+ (aq) + Ni (s) → Cu (s) + Ni2+ (aq) A) (-0.59 ± 0.01) V B) (-0.09 ± 0.01) V C) (0.59 ± 0.01) V D) (0.09 ± 0.01) V --------------------------------------------------------------------------------------------------------- What is the proper line notation for the following reaction? Cu (s) + 2Ag+ (aq) → Cu2+ (aq) + 2Ag (s) A) Cu2+ | Cu || Ag | Ag+ B) Ag+ | Ag || Cu | Cu2+ C) Cu |...
K = 1.3 * 106 for the disproportionation reaction of Cu+ at 298 K. Calculate the E°cell for this rxn at 298K The latimer Diagram for Cu+ has: +0.159 V +0.520 V Cu2+ ---> Cu+ --> Cu(s) And then Cu2+ --> Cu (s) = 0.340 V So for Ecell would I just do Ecell = (0.520V - (-0.159V))? ... if not how come?
The Ksp of CuCl is 1.7×10−7. Find Ecell for the following cell (at 298 K): Cu(s)|CuCl(s)|Cl−(aq)(0.10 M)||Cu+(aq)(0.10 M)|Cu(s)
1- Consider the following redox reaction: Fe(s) + Cu2+(aq) --> Fe2+(aq) + Cu(s) EoCell = 0.78 V If [Cu2+] = 0.3 M, what [Fe2+] is needed so that Ecell = 0.76 V 2- Calculate the Eocell for the following redox reaction: Cu(s) + 2Ag+(aq) --> Cu2+(aq) + 2Ag(s)
Calculate the cell potential for the reaction below when the concentrations of ions are: [Ag+ ] = 0.010 M and [Cu2+] = 0.750 M, at 25 °C. Cu(s) + 2Ag+ (aq) --> Cu2+(aq) + 2Ag(s) Given the standard reduction potentials: Cu2+(aq) + 2e– → Cu(s) Eϴ = 0.34 V Ag+ (aq) + e– → Ag(s) Eϴ = 0.80 V (A) 0.35 V (B) 0.44 V (C) 0.46 V (D) 0.48 V (E) 0.57 V