7. Element R has three isotopes. The isotopes are present in 0.0825, 0.2671, and 0.6504 relative abundance. If their masses are 88, 109, and 122 respectively, calculate the atomic mass of element R.
Atomic mass of element R will be the average atomic mass of all three isotopes present according to the relative abundance.
So Atomic mass of R= (0.0825×88)+(0.2671×109)+(0.6504×122) amu
= 115.7272 amu
And Atomic mass of element R in gram= 115.7272g
= 115.72 g
7. Element R has three isotopes. The isotopes are present in 0.0825, 0.2671, and 0.6504 relative...
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I need 7 and 8 answered Thanks
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