A 60 Hz transformer has been tested with the following results under open circuit test: Primary...
A 60 Hz transformer has been tested with the following results under open circuit test: Primary voltage: 110 V(rms); Primary current: 1A(rms) and Input power: 10 W. Find the equivalent core loss resistance and equivalent magnetizing inductance of the transformer
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A 60 Hz transformer has been tested with the following results
under open circuit test: Primary...
A 60 Hz 20KVA 8000/240 Vrms transformer has the equivalent circuit parameters given in the table...
A 60 Hz 20KVA 8000/240 Vrms transformer has the equivalent circuit parameters given in the table below, a) For the rated load having a lagging power factor of 0.8, find the magnitude of the load current in Amperes. 15 Primary resistance 0.02 econdary resistance 120 Primary leakage reactance X2wL2 0.15 Secondary leakage reactance Xm=wLm Magnetizing reactance 30 k Re 200 k Core-loss resistance Answer: Check b) Find the phase of he load current in degrees (note: sign is important). Answer:...
A 20 kVA, 60 Hz, 2400/240 V single-phase distribution transformer has been tested to determine its...
A 20 kVA, 60 Hz, 2400/240 V single-phase distribution transformer has been tested to determine its equivalent circuit. The results of the test are shown below: Open circuit Test (on low voltage side) Voc=240V, Ioc=1.028A, Poc=122W. Short circuit test (On high voltage side) Vsc=61.3V, Isc=8.33A, Psc=257W. The transformer is supplying power to a load that draws 15 kVA at 240 V. The load power factor is 0.90 lagging. Calculate the voltage regulation for this operation condition.
A 20 KVA 20k/480 V 60 Hz distribution transformer is tested with the following results. Open...
A 20 KVA 20k/480 V 60 Hz distribution transformer is tested with the following results. Open circuit test, measured from the LV, Voc=480V, 10c-1.6A, Poc=268.8W. Short circuit test, measured from the HV, Vsc1130V, ISC1A, PS-395.5W. (a) Find the equivalent circuit of this transformer with all of the impedances referred to the HV side. Re- MAX= ΜΩ Rsc= Ohms X sca Ohms (b) Find the equivalent circuit of this transformer in per unit with respect to its own rated powr. Re-...
A 1000-VA 230/115-V transformer has been tested to determine its equivalent circuit. The results of the...
A 1000-VA 230/115-V transformer has been tested to determine its equivalent circuit. The results of the tests are shown below Open-circuit test Voc= 230 V loc= 0.45 A Poc 30 W Short-circuit test Vsc= 19.1 V lsc=8.7 A Psc= 42.3 W All data given were taken from the primary side of the transformer. Determine all the transformer parameters shown in Fig. 3. jXM Ns V. Ideal transformer Fig. 3
a) Find the magnitude of the input voltage in (V): A 60 Hz 20kVA 8000/240 Vrms...
a) Find the magnitude of the input voltage in (V):
A 60 Hz 20kVA 8000/240 Vrms transformer has the equivalent circuit parameters given in the table below; Primary resistance econdary resistance Primary leakage reactance Secondary leakage reactance Magnetizing reactance Ri R2 X1 = wL1 X2 = wL2 Xm = wLm 15 12 0.02 S2 120 12 0.15 12 30 kN2 Core-loss resistance 200 kS2
Question 31 (17 points) 120/120 single-phase transformer. Calculate the values for the equivalent circuit for the single-phase transformer for the given short and open circuit test shown below. (2 po...
Question 31 (17 points) 120/120 single-phase transformer. Calculate the values for the equivalent circuit for the single-phase transformer for the given short and open circuit test shown below. (2 points) Draw the equivalent circuit. (1 point each) Find Ssc, QSC, Soc, Qoc, R1, R2, XI, X2, Rc, Xm, PFsc, PFoc, (esc θ。c) phase angel between V and I. What is the power rating of this transformer? Short circuit test (performed at High Voltage side) Vsc 16.20V rms, Isc 5.00 A...
Question 2 A single-phase transformer has the following nameplate ratings: 100 kVA, 7200/240 V and 60...
Question 2 A single-phase transformer has the following nameplate ratings: 100 kVA, 7200/240 V and 60 Hz. The following results are obtained from open-circuit and short-circuit tests: Test Open-circuit Short-circuit Voltage 7200 V 250 V Current 0.65 A 13.89 A Real Power Input 425 W 1420 W a) Determine the parameters of this transformer, all referred to the primary side. b) The secondary of this transformer is connected to a load that draws 100% of the rated power at rated...
4. The figure below shows the equivalent circuit of a 2400/240-V, 60-Hz transformer. The high-side leakage...
4. The figure below shows the equivalent circuit of a 2400/240-V, 60-Hz transformer. The high-side leakage impedance is (1.2+j 2.0) 2. the low-side leakage impedance is (0.012 ti 0.02) S2, and Xm at the high-side is 1800 2. Neglect the Hysteresis and Eddy current loss resistance Rhe Calculate the input voltage if the output voltage is 240 V (rms). Given the load resistance is 1.5 12 and the power factor is 0.8 (lagging). ཉིས་པ་དེ། དེ་ | ༼ ། ༼། །
Problem 3 A 50-Hz transformer is operated from a 60 Hz supply. Assume that the load...
Problem 3 A 50-Hz transformer is operated from a 60 Hz supply. Assume that the load does not change. Discuss the corresponding effects on its flux, reactive power requirements, losses, and efficiency. а- [5 Points] A 50-kVA, 2400/240 V, 60-Hz, single-phase distribution transformer has the following equivalent circuit parameters referred to the high-voltage side Xea 3.0 Req= 0.5 Xm 4,500 S2 Use the equivalent Cantilever model circuit shown in Figure (1). Assume that the load on the secondary of the...
Choose the base power as 50-KVA, the primary base voltage as 2400-V, the secondary voltage as...
Choose the base power as 50-KVA, the primary base voltage as 2400-V, the secondary voltage as 240-V: (a) Calculate and sketch the transformer equivalent circuit in per unit values' (b) The transformer is carrying rate load of 1.0 pu at.8 power factor lagging. Calculate the primary voltage in per unit. (c) Calculate the efficiency of the transformer at this load. A 50-KVA 2400/240-V, 60-Hz distribution transformer is tested with the following results: Open circuit Test Short Circuit Test Voc =...
A 60 Hz 20KVA 8000/240 Vrms transformer has the equivalent circuit parameters given in the table below, a) For the rated load having a lagging power factor of 0.8, find the magnitude of the load current in Amperes. 15 Primary resistance 0.02 econdary resistance 120 Primary leakage reactance X2wL2 0.15 Secondary leakage reactance Xm=wLm Magnetizing reactance 30 k Re 200 k Core-loss resistance Answer: Check b) Find the phase of he load current in degrees (note: sign is important). Answer:...
A 20 KVA 20k/480 V 60 Hz distribution transformer is tested with the following results. Open circuit test, measured from the LV, Voc=480V, 10c-1.6A, Poc=268.8W. Short circuit test, measured from the HV, Vsc1130V, ISC1A, PS-395.5W. (a) Find the equivalent circuit of this transformer with all of the impedances referred to the HV side. Re- MAX= ΜΩ Rsc= Ohms X sca Ohms (b) Find the equivalent circuit of this transformer in per unit with respect to its own rated powr. Re-...
A 1000-VA 230/115-V transformer has been tested to determine its equivalent circuit. The results of the tests are shown below Open-circuit test Voc= 230 V loc= 0.45 A Poc 30 W Short-circuit test Vsc= 19.1 V lsc=8.7 A Psc= 42.3 W All data given were taken from the primary side of the transformer. Determine all the transformer parameters shown in Fig. 3. jXM Ns V. Ideal transformer Fig. 3
a) Find the magnitude of the input voltage in (V):
A 60 Hz 20kVA 8000/240 Vrms transformer has the equivalent circuit parameters given in the table below; Primary resistance econdary resistance Primary leakage reactance Secondary leakage reactance Magnetizing reactance Ri R2 X1 = wL1 X2 = wL2 Xm = wLm 15 12 0.02 S2 120 12 0.15 12 30 kN2 Core-loss resistance 200 kS2
Question 31 (17 points) 120/120 single-phase transformer. Calculate the values for the equivalent circuit for the single-phase transformer for the given short and open circuit test shown below. (2 points) Draw the equivalent circuit. (1 point each) Find Ssc, QSC, Soc, Qoc, R1, R2, XI, X2, Rc, Xm, PFsc, PFoc, (esc θ。c) phase angel between V and I. What is the power rating of this transformer? Short circuit test (performed at High Voltage side) Vsc 16.20V rms, Isc 5.00 A...
Question 2 A single-phase transformer has the following nameplate ratings: 100 kVA, 7200/240 V and 60 Hz. The following results are obtained from open-circuit and short-circuit tests: Test Open-circuit Short-circuit Voltage 7200 V 250 V Current 0.65 A 13.89 A Real Power Input 425 W 1420 W a) Determine the parameters of this transformer, all referred to the primary side. b) The secondary of this transformer is connected to a load that draws 100% of the rated power at rated...
4. The figure below shows the equivalent circuit of a 2400/240-V, 60-Hz transformer. The high-side leakage impedance is (1.2+j 2.0) 2. the low-side leakage impedance is (0.012 ti 0.02) S2, and Xm at the high-side is 1800 2. Neglect the Hysteresis and Eddy current loss resistance Rhe Calculate the input voltage if the output voltage is 240 V (rms). Given the load resistance is 1.5 12 and the power factor is 0.8 (lagging). ཉིས་པ་དེ། དེ་ | ༼ ། ༼། །
Problem 3 A 50-Hz transformer is operated from a 60 Hz supply. Assume that the load does not change. Discuss the corresponding effects on its flux, reactive power requirements, losses, and efficiency. а- [5 Points] A 50-kVA, 2400/240 V, 60-Hz, single-phase distribution transformer has the following equivalent circuit parameters referred to the high-voltage side Xea 3.0 Req= 0.5 Xm 4,500 S2 Use the equivalent Cantilever model circuit shown in Figure (1). Assume that the load on the secondary of the...
Choose the base power as 50-KVA, the primary base voltage as 2400-V, the secondary voltage as 240-V: (a) Calculate and sketch the transformer equivalent circuit in per unit values' (b) The transformer is carrying rate load of 1.0 pu at.8 power factor lagging. Calculate the primary voltage in per unit. (c) Calculate the efficiency of the transformer at this load. A 50-KVA 2400/240-V, 60-Hz distribution transformer is tested with the following results: Open circuit Test Short Circuit Test Voc =...
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