What is the mass of a piece of aluminum that starts at 100oC, is immersed in a calorimeter with 200 g of water at 25.0oC, and causes the water to rise to a temperature of 29.5oC?
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200.0 g |
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53.4 g |
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59.3 g |
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4,184.0 g |
m(water) = 200.0 g
T(water) = 25.0 oC
C(water) = 4.184 J/goC
m(metal) = to be calculated
C(metal) = 0.902 J/goC
T = 29.5 oC
We will be using heat conservation equation
use:
heat lost by metal = heat gained by water
m(metal)*C(metal)*(T(metal)-T) = m(water)*C(water)*(T-T(water))
m(metal)*0.902*(100.0-29.5) = 200.0*4.184*(29.5-25.0)
m(metal)*63.591 = 3765.6
m(metal)= 59.3 g
Answer: 59.3 g
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