5) Calculate Kc for the reaction CH3COOH (aq) ⇌ CH3COO- (aq) + H+ (aq) from the following equilibrium concentrations. [CH3COOH] = 1.65 x 10-2 M, [CH3COO-] = 5.44 x 10-4 M, [H+] = 5.44 x 10-4 M.
5) Calculate Kc for the reaction CH3COOH (aq) ⇌ CH3COO- (aq) + H+ (aq) from the...
5. Given that CH3COOH(aq) ⇌ H+(aq) + CH3COO–(aq), Ka = 1.83 × 10–5 at 25.00 °C. Calculate the reaction quotient Q, ΔG°, and ΔG for a solution at 25.00 °C in which the initial concentrations are: [CH3COOH]0 = 0.10 M, [H+]0 = 4.5 × 10–5 M, [CH3COO–]0 = 0.010 M
1. Consider the following reaction at equilibrium. CH3COOH (aq) = CH3COO- (aq) + H+ (aq) a) When NaOH is added to the solution, write the reaction that occurs. (What does the OH react with?) b) When NaOH is added to the solution, will the concentration of each of the following species increase, decrease, or remain the same? Explain your answer. [H"] [CH,C00] [CH2COOH)
At equilibrium, acetic acid (CH3COOH) partially dissociates into a proton (H+) and the acetate ion (CH3COO-). An equilibrium mixture contains 0.0990 M acetic acid, 1.33×10-3M acetate, and 1.33×10-3M proton. What is the value of Kc for this reaction?
For the equilibrium below, the initial concentration of CH3COOH is 0.0100M with no H3O + or CH3COO- . At equilibrium, the [H3O + ] is found to be 4.10 x 10-4 . Calculate Kc for the reaction. ( Make an ICE table with only numbers). CH3COOH (aq) + H2O (l) ↔ CH3COO- (aq) + H3O + (aq)
For the reaction NH3(aq) + H+ (aq) ⇋ NH4 + (aq), at 20°C the equilibrium concentrations were as follows: [NH3] = 2 x 10-4 M; [H+ ] = 2 x 10-4 M; and [NH4 + ] = 18 M. Calculate the equilibrium constant for the reaction.
Calculate the MOLES of
HA (CH3COOH) and MOLES of A- (CH3COO-) present in the solution.
Remember, you started with 50.0 mL of 1.0 M solution for each
• The pKa of CH3COOH
is 4.76. Use this information with the moles of acid and moles of
base to calculate the pH of this solution.
Stockroom Information Name: 1M CH3COOH Volume: 50.000 mL Species (aq) Molarity 0.00417456 1M CH3COOH 50.000 mL @ 25.0°C H+ OH 2.41858e-12 0.995825 CH3COOH CH3COO 0.00417456 Temperature: 25.00°C...
Given the equilibrium constants for the equilibria, 2 NH4+(aq) + 2 H2O(ª) 2 NH3(aq) + 2 H3O+(aq); Kc = CH3COOH(aq) + H2O(ª) CH3COO−(aq) + H3O+(aq); Kc = determine Kc for the following equilibrium. CH3COOH(aq) + NH3(aq) CH3COO−(aq) + NH4+(aq) a. 3.08 × 104 b. 9.96 × 10-15 c. 3.25 × 10-5 d. 1.75 × 10-5 e. 1.00 × 1014
The following reactions all have K < 1. 1) CH3COO- (aq) + HClO (aq) CH3COOH (aq) + ClO- (aq) 2) ClO- (aq) + C6H5OH (aq) HClO (aq) + C6H5O- (aq) 3) C6H5OH (aq) + CH3COO- (aq) C6H5O- (aq) + CH3COOH (aq) Arrange the substances based on their relative BASE strength. CH3COOH ClO- HClO C6H5OH CH3COO- C6H5O- strongest base intermediate base weakest base not a Bronsted-Lowry base
The following reactions all have K > 1. 1) CH3COO- (aq) + HCOOH (aq) CH3COOH (aq) + HCOO- (aq) 2) C6H5O- (aq) + HCOOH (aq) HCOO- (aq) + C6H5OH (aq) 3) CH3COOH (aq) + C6H5O- (aq) C6H5OH (aq) + CH3COO- (aq) Arrange the substances based on their relative base strength. Clear All C6H5O- HCOO- C6H5OH HCOOH CH3COOH CH3COO- strongest base intermediate base weakest base not a Bronsted-Lowry base
The following reactions all have K<1. 1) CH3COO" (aq) + CH3COOH (aq) =CH COOH (aq) + CH3C00" (aq) 2) NO2 (aq) + CH2COOH(aq) – CH3C00" (aq) + HNO2 (aq) 3) CHCOOH (aq) + NO2 (aq) = HNO2 (aq) + CH3COO(aq) Arrange the substances based on their relative acid strength. Clear All NO2 ΗΝΟ, strongest acid CHC00 intermediate acid CH3COOH weakest acid CH3COOH not a Bronsted-Lowry acid CH3COO