why is important to have a small for the armature resistance of an electric motor?
An electric motor is designed with low armature resistance because
1) we know that copper losses = I^2*R
Where I = current passing through armature winding
R= armature resistance
So copper losses are directly proportional to armature resistance
Therefore in order to have less copper losses , armature resistance should be small
2) resistance dissipates energy in the form of heat . So, higher the resistance higher the heat dissipation . If heat dissipation is more windings may burn , insulation may lost and motor doesn't work properly so to reduce all these heat dissipation should be low
Therefore resistance must be low for low heat dissipation
3)we know that electromagnetic torque(Te) directly proportional to armature current . So, for the large generation of the torque current should be high .to produce large current armature resistance should be small
4) Armature resistance should be small for better performance of the motor . general for large rated machines armature resistance in the range of 0.1- 0.5 ohms
5) efficiency increases when the resistance is low in electric motor
why is important to have a small for the armature resistance of an electric motor?
The armature windings of a dc motor have a resistance of 8.0 Ω . The motor is connected to a 120-V line, and when the motor reaches full speed against its normal load, the back emf is 108 V. The load is increased so it causes the motor to run at half speed. What will be the current in the motor in this case? (Express your answer to two significant figures and include the appropriate units.)
1) A 220V dc motor has an armature resistance of 0.5 Ω. The full load armature current is 20 A. The starting torque of the motor is 880 N-m, Find the full load speed of the motor. 2) A 220V dc motor developing 25 hp (18.65 kW) runs at a speed of 1000 r.p.m.. Calculate the torque in N-m if the efficiency of the motor is 90%.
A 240V ,1500rpm separately excited motor has the armature resistance of Ra=0.1ohm.The motor current is 30A. a) Draw the equivalent circuit of the motor b) Find the armature current (Ia) in ampere
A shunt motor has an armature resistance of 0.25 W. The motor takes 125 A from a 400 V supply and runs at 1000 rpm. If the total torque developed remains unchanged, calculate the speed and armature current if the magnetic field is reduced to 80% of the initial value.
A simple electric motor consists of a cylindrical armature with
a coil around it. A battery feeds current into the coil and this
produces a magnetic field around the it and so the armature became
an electromagnet. The magnetic field interacts with the armature
that generate a rotation. The commutator can change the direction
of the current every half-turn. This component can reverse the
north and the south poles of the armature and it create a rotation.
QUESTION
1....
3. A 25-kW, 230-V shunt motor has an armature resistance of 0.064 Ω and a field-circuit resistance of 95 Ω. The motor delivers rated output power at rated voltage when its armature current is 122 A. When the motor is operating at rated voltage, the speed is observed to be 1150 r/min when the machine is loaded such that the armature current is 69.5 A a. Calculate the rated-load speed of this motor In order to protect both the motor...
A 240V,1500rpm separately excited motor has the armature resistance of Ra=0.1ohm.The motor current is 30A a) draw the equivalent circuit of the motor b)find cthe armature current Ia in ampere c)Find the electromotive force in volts d)Find the mechanical output power developed by the motor in watts e)calculate the efficiency of the motor in percentage f) calculate the mechanical torque produced by the motor in Nm
A d.c shunt motor has armature and field resistance of 0.2 Ω and 110 Ω respectively. The motor is running at 1200 rpm and drawing 15 A from 110 V supply. If the field resistance is decreased by 10%, calculate the new steady state armature current and speed of the motor. Assume the load torque to be constant
A d.c shunt motor has armature and field resistance of 0.2 Ω and 110 Ω respectively. The motor is running at 1200 rpm and drawing 15 A from 110 V supply. If the field resistance is decreased by 10%, calculate the new steady state armature current and speed of the motor. Assume the load torque to be constant.
1. A 300 V compound motor has armature resistance 0.18 Ω, series field resistance 0.3 Ω and shunt field resistance 100 Ω. The rotational losses are 200 W. On full load the line current is 25 A and the motor runs at 1800 rpm. Determine: (i) the developed mechanical power (ii) the output power (iii) the output torque (iv) the efficiency at full load 2. A 120 V series motor has 0.2 Ω field resistance. On full load, the line...