Question

C++ SOURCE CODE P0\/\/|\|3D. In the early 80s, hackers used to write in an obfuscated, but mostly readable way called “leet” – short for “elite”. In essence, it was a simple character replacement algorithm, where a single “regular” character was replaced by one or more “leet” characters; numbers remained the same. Here’s one of the most readable versions: a 4 g 9 m /\\/\\ s $ y ‘/ b B h |-| n |\\| t 7 z Z c ( i 1 o 0 u U d D j j p P v \\/ e 3 k |< q Q w \\/\\/ f Ph l L r R x >< Note! You will need to know how to 1) get the length of a string (the number of characters) and 2) access individual characters of the string. See the appendix for more information. You must use at least one method in addition to main – preferably one that translates individual characters! Note #2: your first task should be to try to print out a single ‘\’ character… Sample run 1: Enter a string: you have been powned '/0U |-|4\\/3 B33|\\| P0\\/\\/|\\|3D Sample run 1: Enter a string: you have programming skrilz '/0U |-|4\\/3 PR09R4/\\/\\/\\/\\1|\\|9 $|

Answer 1

#include<iostream>

using namespace std;

string translate(char letter)
{
   string leet[]={"4","B","(","D","3","Ph","9","|-|","1","j","|<","L","/\\/\\",
   "|\\|","0","P","Q","R","$","7","U","\\/","\\/\\/","><","'/","Z"};
   return leet[letter-97];
}

int main(){
   string line,leeted="";
   cout<<"Enter a string: ";
   getline(cin,line);
   for(int i=0;i<line.size();i++){
       if(line[i]>=97 && line[i]<=122){
           leeted+=translate(line[i]);
       }
       else
       leeted+=line[i];
   }
   cout<<leeted<<endl;
   return 0;
}