Suppose the surface-catalyzed hydrogenation reaction of an unsaturated hydrocarbon has a rate constant of 0.796 M/min....
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Suppose the surface-catalyzed hydrogenation reaction of an unsaturated hydrocarbon has a rate constant of 0.796 M/min. The reaction is observed to follow zero-order kinetics. If the initial concentration of the hydrocarbon is 6.70 M, what is the half-life of the reaction in seconds?
*Please report 3 significant figures. Numbers only, no unit. No scientific notation.
Homework Answers
The formula for the half life of a zero order reaction is as follows:
where, a is the inital concentration; K0 is the rate constant for a zero order reaction.
So, all of the required values are provided in the question, so this is a straight forward question.
Now, putting the values into the aforementioned formula:
Converting the value of half life into seconds:
Add Answer to:
Suppose the surface-catalyzed hydrogenation reaction of an
unsaturated hydrocarbon has a rate constant of 0.796
M/min....
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