Question

(python) Leap Year Detector
Design a program that asks the user to enter a year, and then displays a message indicating whether that year is a leap year or not. Use the following logic to develop your algorithm:
If the year is evenly divisible by 100 and is also evenly divisible by 400, then it is a leap year. For example, 2000 is a leap year but 2010 is not.
If the year is not evenly divisible by 100, but it is evenly divisible by 4, it is a leap year. For example, 2008 is a leap year but 2009 is not.

Answer 1

year = int(input("Enter an year: "))

if year % 4 == 0:
    if year % 100 == 0:
        is_leap_year = False
        if year % 400 == 0:
            is_leap_year = True
    else:
        is_leap_year = True
else:
    is_leap_year = False

if is_leap_year:
    print("The year", year, "is a leap year")
else:
    print("The year", year, "is not a leap year")