Question

This is for C++

The mathematician John Horton Conway invented the “Game of Life.” Though not a “game” in any traditional sense, it provides interesting behavior that is specified with only a few rules. This project asks you to write a program that allows you to specify an initial configuration. The program follows the rules of Life (listed shortly) to show the continuing behavior of the configuration.

LIFE is an organism that lives in a discrete, two-dimensional world. While this world is actually unlimited, we do not have that luxury, so we restrict the array to 80 characters wide by 22 character positions high. If you have access to a larger screen, by all means use it.

This world is an array with each cell capable of holding one LIFE cell. Generations mark the passing of time. Each generation brings births and deaths to the LIFE community. The births and deaths follow this set of rules:

1. We define each cell to have eight neighbor cells. The neighbors of a cell are the cells directly above, below, to the right, to the left, diagonally above to the right and left, and diagonally below, to the right and left.

2. If an occupied cell has zero or one neighbor, it dies of loneliness. If an occupied cell has more than three neighbors, it dies of overcrowding.

3. If an empty cell has exactly three occupied neighbor cells, there is a birth of a new cell to replace the empty cell.

4. Births and deaths are instantaneous and occur at the changes of generation. A cell dying for whatever reason may help cause birth, but a newborn cell cannot resurrect a cell that is dying, nor will a cell’s death prevent the death of another, say, by reducing the local population.

*

Examples: *** becomes * then becomes *** again, and so on.

*

Notes: Some configurations grow from relatively small starting configurations. Others move across the region. It is recommended that for text output you use a rectangular char array with 80 columns and 22 rows to store the LIFE world’s successive generations. Use an * to indicate a living cell and use a blank to indicate an empty (or dead) cell. If you have a screen with more rows than that, by all means make use of the whole screen.

Suggestions: Look for stable configurations. That is, look for communities that repeat patterns continually. The number of configurations in the repetition is called the period. There are configurations that are fixed, that is, that continue without change. A possible project is to find such configurations.

Hints: Define a void function named generation that takes the array we call world , an 80-column by 22-row array of type char , which contains the initial configuration. The function scans the array and modifies the cells, marking the cells with births and deaths in accord with the rules listed previously. This involves examining each cell in turn and either killing the cell, letting it live, or, if the cell is empty, deciding whether a cell should be born. There should be a function display that accepts the array world and displays the array on the screen. Some sort of time delay is appropriate between calls to generation and display . To do this, your program should generate and display the next generation when you press Return. You are at liberty to automate this, but automation is not necessary for the program.

Answer 1

The code would be:

#include<iostream>
#include<stdio.h>

using namespace std;
void Display(const int gen[][80],int genNum);
void Generation(int gen[][80]);
int aLive(int gen[][80]);
void dieBorn(int geb[][80],int succ[][80],int neigbr,int i,int j);
void copy(int a[][80],int b[][80]);
int check(int gen[][80],int i,int j);

int main()
{
   char c;
   int world[22][80] = {0};
   int row,col,gen = 0;
   char backspace = 0;
   bool cntr = true;
   while(cntr==true)
   {
       do
       {
           cout<<"Enter row index of cell(0-21):";
           cin>>row;
       }while(row<0 || row>21);
       do
       {
           cout<<"Enter column index of cell(0-79):";
           cin>>col;
       }while(col<0 || col>79);
       world[row][col] = 1;
       cout<<"Cell [ "<<row<<"]["<<col<<"] is alive!\n";
       cout<<"\nTo mark another cell?press(y/n):";
       do
       {
           cout<<backspace;
           cin>>c;
       }while(c!='y'&&c!='Y'&&c!='n'&&c!='N');
       if(c=='n'||c=='N')
       {
           cntr = false;
       }
   }
   Display(world,gen);
   while(aLive(world))
   {
       Generation(world);
       gen++;
       int x,y;
       for(x=0;x<2000;x++)
       {
           for(y=0;y<200000;y++)
           {
           }
       }
       if(aLive(world)==0)
       {
           cout<<"\n\tAll LIFE has died out.\n";
       }
       else
       {
           Display(world,gen);
       }
   }
   cout<<"\n\nPress any key to exit:";
   cin.get();
   cin.get();
   return 0;
}

int aLive(int gen[][80])
{
   for(int i=0;i<22;i++)
   {
       for(int j=0;j<80;j++)
       {
           if(gen[i][j] == 1)
           {
               return 1;
           }
       }
   }
   return 0;
}

void Display(const int gen[][80],int genNum)
{
   cout<<"\n\nGeneration " << genNum <<":\n\n";
   for(int i=0;i<22;i++)
   {
       for(int j=0;j<80;j++)
       {
           cout<<gen[i][j];
       }
       cout<<endl;
   }
   return;
}
void Generation(int world[][80])
{
   int neigbr = 0;
   int i,j;
   int succ[22][80];
   for(i=0;i<22;i++)
   {
       for(j=0;j<80;j++)
       {
           neigbr = check(world,i,j);
           dieBorn(world,succ,neigbr,i,j);
       }
   }
   copy(succ,world);
   return;
}
int aLive(const int gen[][80])
{
   for(int i=0;i<22;i++)
   {
       for(int j=0;j<80;j++)
       {
           if(gen[i][j] == 1)
           {
               return 1;
           }
       }
   }
   return 0;
}
void copy(int a[][80],int b[][80])
{
   for(int i=0;i<22;i++)
   {
       for(int j=0;j<80;j++)
       {
           b[i][j] = a[i][j];
       }
   }
   return;
}
int check(int gen[][80],int i,int j)
{
   int neigbr = 0;
   if(((i-1)>=0)&&((j-1)>=0)&&(gen[i-1][j-1] == 1))
   {
       neigbr++;
   }
   if(((i-1)>=0)&&(gen[i-1][j] == 1))
   {
       neigbr++;
   }
   if(((i-1)>=0)&&((j+1)<80)&&(gen[i-1][j+1] == 1))
   {
       neigbr++;
   }
   if(((j-1)>=0)&&(gen[i][j-1] == 1))
   {
       neigbr++;
   }
   if(((j+1)<80)&&(gen[i][j+1] == 1))
   {
       neigbr++;
   }
   if(((i+1)<22)&&((j-1)>=0)&&(gen[i+1][j-1] == 1))
   {
       neigbr++;
   }
   if(((i+1)<22)&&(gen[i+1][j] == 1))
   {
       neigbr++;
   }
   if(((i+1)<22)&&((j+1)<80)&&(gen[i+1][j+1] == 1))
   {
       neigbr++;
   }
   return neigbr;
}
void dieBorn(int gen[][80],int succ[][80],int neigbr,int i,int j)
{
   if(neigbr>3&&gen[i][j] == 1)
   {
       succ[i][j] = 0;
       cout<<"\n\tCell ["<<i<<"]["<<j<<"]dies of overcrow of "<<neigbr<<" neighbour,";
   }
   else if(neigbr<=1 && gen[i][j] == 1)
   {
       succ[i][j] = 0;
       cout<<"\n\tCell ["<<i<<"]["<<j<<"]dies of loneliness from having "<<neigbr<<" neighbour,";
   }
   else if(neigbr == 3&&gen[i][j] == 0)
   {
       succ[i][j] = 1;
       cout<<"\n\tCell ["<<i<<"]["<<j<<"]is born from having "<<neigbr<<" neighbour,";
   }
   else
   {
       succ[i][j] = gen[i][j];
       return;
   }
}

The screenshot of code and output:

I hope the code would help you, and if you have any doubt please ask in the comments section.

If you did like my code, please do give a thumbs up!!!