calulate the # of generation, generation time and growth rate for the following e coli bactetia...
Homework Answers
- Total time = t= 5 hours = 5 x 60 =300 minutes
- Initial number of cells = N1=100,000
- Final number of cells = N2 = 100,000,000
- Number of generation = n = (log N2 – log N1)/ log 2
- Number of generation = n = (log 100,000,000- log 100,000)/ 0.301 = (8-5) / 0.301 = 3/0.301 =9.97 = 10 (approx).
- Generation time= G = t/n = 300/10 =30 minutes = 2 hours
- Growth rate = K = 1/G = ½ = 2 doubling per hour.
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