a first order process has an experimentally determined rate constant of 6.0 x 10^-4 at 500 C if the initial conc of the species is 0.0226 mol/L calc it conc after 955 secs
first order has the integrated law equation is as
follows
ln[A]t = -Kt + ln[A]o
where [A]o = initial concentration = 0.0226 M
K = 6.0*10-4
t = 955 sec
[A]t = concentration at time
substituting the values in the equation
ln[A]t = - 6.0*10-4 * 955 + ln [0.0226 ]
ln[A]t = - 6.0*10-4 * 955 + (-3.7898)
ln[A]t = - 6.0*10-4 * 955 -3.7898
[A]t = 0.01274 M
answer => 0.0127 M
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Ch.19 #4
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