Answer=
The given are
The isotope H-3 has a half life (t1/2) = 7.02 years.
T = 49 years
If you start with an initial H-3 mass of 100.0g.
Initial reactivity N0 = 100 gm
T = n X t1/2
n = T / t1/2
n = 49 / 7.02
= 6.980
Formula is
N = N0 (1/2)n
= 100 ( 1/2 ) 6.98
= 100 X (1/126.23 )
=0.792
The approximate amount remaining after 49 years of decay = 0.792 gms .
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