A 36.2-g sample of metal at 94.7oC is mixed with water (initially at 25.4oC) in a...
A 36.2-g sample of metal at 94.7oC is mixed with water (initially at 25.4oC) in a calorimeter. If the calorimeter constant is 46.2 J/K, final temperature is found to be 28.8oC, and the amount of heat absorbed by the water was determined to be 943 J, calculate the specific heat of the metal.
Homework Answers
We have the heat transfer equation, Q = m * C * 
T,
where m is mass of metal, C is the Specific heat constant and
T is the
temperature change. Since the calorimeter absorbed 943 J,
Substituting The values:
943 = 36.2 * 10 -3 * C * (94.7 - 28.8)
Solving, we have: C = 395.29 J / kg-K
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A 36.2-g sample of metal at 94.7oC is mixed with
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