Modify your model to represent an individual of genotype Aa Cc in which the genes are...
Modify your model to represent an individual of genotype Aa Cc in which the genes are linked with A and c on one homolog and a and C on the other.
8) Use the model to demonstrate the effect of linkage on the gametes produced in meiosis. What gamete types are expected in highest frequency? Why?
What gametes are expected in lower frequency? How are these formed?
Diagram the process of meiosis demonstrating how the different gamete types are formed.
Homework Answers
The genotype of the model organism is AaCc.
'A' allele is linked with allele 'c' in one homolog and 'a' allele is linked with 'C' on the other homolog.
8)
So, when meiosis will happen there will be a possibility of formation of 4 different types of gametes. Among them, 2 will be parental type (i.e. Ac and aC) and the other two will be recombinant type (i.e. AC and ac). As these two alleles are linked, the possibility of recombination very less.
So, the gametes with the parental type will produce in higher frequency and recombinant type will be produced in lower frequency by the process of recombination.
The following image will give a detail about the recombination process if occur, otherwise, the parental type will be directly inherited without recombination (as those alleles are linked).
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Modify your model to
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13.
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The results for the F2 progeny are shown for a F1 cross using the two X-linked...
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- a double mutant male (white eye, miniature wing):
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in the female? Why or why not?
2)...
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1.
2.
13.
Which statement explains why the recombination frequency between two genes is always less than 50%? Recombination cannot be more than 50% because chromosomes are only 50 map units in length. The genotype of the F, gametes will always be 50% parental gametes and 50% recombinant gametes. Genes with a recombination frequency near 50% are unlinked and have an equal likelihood of being inherited together or separately. F1 gametes always have 50% of their alleles from each parental...
The results for the F2 progeny are shown for a F1 cross using
the two X-linked markers:
w+ and m+.
As shown in the figure, the F1 cross is between the following
two parents:
- a phenotypically wild-type (red eye, full wing), heterozygous
female: w+m+/wm
- a double mutant male (white eye, miniature wing):
wm/Y
Answer the following questions:
1) In the F1 cross, can you infer the genotype for the phenotype
in the female? Why or why not?
2)...
please solve qs12-23 and include explanations thanks
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