For the reaction
N2(g)+O2(g) = 2NO(g); relate the rate of disappearance of N2 to the rate of formation of NO
Answer
Given chemical reaction is,
N2(g)+O2(g)=2NO(g)
Rate of disappearance of N2 is given as,
Rate of disappearance of N2 = -d[N2]/dt
Rate of formation of NO is given as,
Rate formation of NO = 1/2 d[NO]/dt
Since for the given reaction rate of disappearance of N2 is equal to the twice of rate of formation of NO is given as
Rate= -d[N2]/dt= 1/2 d[NO]/dt
For the reaction N2(g)+O2(g) = 2NO(g); relate the rate of disappearance of N2 to the rate...
2NO(g)+O2(g)→2NO2(g) For the above reaction, the following data were collected for the rate of disappearance of NO in the reaction: Experiment [NO] (M) [O2] (M) Initial Rate (M/s) 1 0.0126 0.0125 1.41×10−2 2 0.0252 0.0250 1.13×10−1 3 0.0252 0.0125 5.64×10−2 Part A: What are the units of the rate constant? a) s−1 b) M−1s−1 c) M−2s−1 d) M−3s−1 Part B: What is the rate of disappearance of NO when [NO]=0.0725 and [O2]=0.0100? Express the rate in molarity per second to...
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