At the Hard Rock Café, like many organizations, project management is a key planning tool. Tomasso is in charge of the Rockfest event, which is attended by well over 100,000 enthusiastic fans. The challenge is pulling it off within 5-month planning horizon. Tomasso identifies activities, their immediate predecessors and time estimates as shown in the table below. As a chief project manager, you have been asked to prepare a report for your company. This report needs to address the concerns of the following: (a) Introduction (b) An explanation of the model and the methodology used (i.e. CPM and PERT). (c) Display your estimated outputs using tables and graphs as well as network diagram. (d) A discussion of the results estimated. (e) Any other comments you feel relevant to the issues being addressed. (f) Conclusion and recommendations. HINT: 1) Determine the project network, critical path, expected time duration. 2) What is the probability that the project can be completed within 5 months? . Table1: Managing Hard Rock’s Rockfest Activity Activity Description Immediate Predecessor Duration (days) o- m- p a Finalize site and building contracts - 1-10-15 b Set police and fire security plan a 1-5-8 c Hire director a 3-5-7 d Develop site plan c 10-14-21 e Set venue capacity d 5-10-12 f Set TV deal c 1-2-4 g Plan for TV camera placement f 3-5-7 h Select local promoter a 6-14-20 i Passes and stage credentials h 3-6-10 j Sound and staging h 15-22-30 k Power, plumbing, AC, toilet services a 3-10-15 l Hire operations manager h 14-25-40 m Hire production manager l 7-12-20 n Hire sponsor coordinator m 10-15-25 o Finalize sponsors n 30-45-60 p Target headline entertainers l 3-7-10 q Target support entertainers p 2-5-8 r Travel accommodations for talent q 10-12-16 s Define signage for sponsors r,o 2-4-7 t Ticketmaster contract p 10-18-21 u Travel accommodations for staff p 1-2-3 v On-site ticketing k,b,g,e,i,j 0.5-0.5-0.5 w Final control s,t,u,v 0.5-0.5-0.5 son - w
Project scheduling with uncertain activity times (Optimistic, Most likely, Pessimistic)
| a | - | 1 | 10 | 15 |
| b | a | 1 | 5 | 8 |
| c | a | 3 | 5 | 7 |
| d | c | 10 | 14 | 21 |
| e | d | 5 | 10 | 12 |
| f | c | 1 | 2 | 4 |
| g | f | 3 | 5 | 7 |
| h | a | 6 | 14 | 20 |
| i | h | 3 | 6 | 10 |
| j | h | 15 | 22 | 30 |
| k | a | 3 | 10 | 15 |
| l | h | 14 | 25 | 40 |
| m | l | 7 | 12 | 20 |
| n | m | 10 | 15 | 25 |
| o | n | 30 | 45 | 60 |
| p | l | 3 | 7 | 10 |
| q | p | 2 | 5 | 8 |
| r | q | 10 | 12 | 16 |
| s | r,o | 2 | 4 | 7 |
| t | p | 10 | 18 | 21 |
| u | p | 1 | 2 | 3 |
| v | k,b,g,e,l,j | 0.5 | 0.5 | 0.5 |
| w | s,t,u,v | 0.5 | 0.5 | 0.5 |
| son | w | 0 | 0 | 0 |
Expected time of each activity,
| Activity | to | tm | tp | te=(to+4⋅tm+tp)/6 | σ2=(tp-to/6)2 |
| a | 1 | 10 | 15 | 9.33 | 5.44 |
| b | 1 | 5 | 8 | 4.83 | 1.36 |
| c | 3 | 5 | 7 | 5 | 0.44 |
| d | 10 | 14 | 21 | 14.5 | 3.36 |
| e | 5 | 10 | 12 | 9.5 | 1.36 |
| f | 1 | 2 | 4 | 2.17 | 0.25 |
| g | 3 | 5 | 7 | 5 | 0.44 |
| h | 6 | 14 | 20 | 13.67 | 5.44 |
| i | 3 | 6 | 10 | 6.17 | 1.36 |
| j | 15 | 22 | 30 | 22.17 | 6.25 |
| k | 3 | 10 | 15 | 9.67 | 4 |
| l | 14 | 25 | 40 | 25.67 | 18.78 |
| m | 7 | 12 | 20 | 12.5 | 4.69 |
| n | 10 | 15 | 25 | 15.83 | 6.25 |
| o | 30 | 45 | 60 | 45 | 25 |
| p | 3 | 7 | 10 | 6.83 | 1.36 |
| q | 2 | 5 | 8 | 5 | 1 |
| r | 10 | 12 | 16 | 12.33 | 1 |
| s | 2 | 4 | 7 | 4.17 | 0.69 |
| t | 10 | 18 | 21 | 17.17 | 3.36 |
| u | 1 | 2 | 3 | 2 | 0.11 |
| v | 0.5 | 0.5 | 0.5 | 0.5 | 0 |
| w | 0.5 | 0.5 | 0.5 | 0.5 | 0 |
| son | 0 | 0 | 0 | 0 | 0 |
The earliest and latest expected time for each activity is calculated by considering the expected time te
| Activity | Immediate Predecessors | Duration |
| a | - | 9.33 |
| b | a | 4.83 |
| c | a | 5 |
| d | c | 14.5 |
| e | d | 9.5 |
| f | c | 2.17 |
| g | f | 5 |
| h | a | 13.67 |
| i | h | 6.17 |
| j | h | 22.17 |
| k | a | 9.67 |
| l | h | 25.67 |
| m | l | 12.5 |
| n | m | 15.83 |
| o | n | 45 |
| p | l | 6.83 |
| q | p | 5 |
| r | q | 12.33 |
| s | r,o | 4.17 |
| t | p | 17.17 |
| u | p | 2 |
| v | k,b,g,e,l,j | 0.5 |
| w | s,t,u,v | 0.5 |
| son | w | 0 |
Edge and it's preceded and succeeded node
| Edge | Node1 → Node2 |
| a | 1→2 |
| c | 2→3 |
| h | 2→7 |
| k | 2→9 |
| b | 2→19 |
| d | 3→4 |
| f | 3→6 |
| e | 4→5 |
| d | 5→10 |
| d | 5→19 |
| g | 6→19 |
| j | 7→8 |
| l | 7→10 |
| i | 7→19 |
| v | 8→17 |
| d | 9→19 |
| d | 10→8 |
| m | 10→11 |
| p | 10→14 |
| n | 11→12 |
| o | 12→13 |
| s | 13→16 |
| q | 14→15 |
| t | 14→16 |
| u | 14→17 |
| r | 15→13 |
| d | 16→17 |
| w | 17→18 |
| son | 18→19 |
The critical path of the
project is: 1-2-7-10-11-12-13-16-17-18-19 and critical activities
are a,h,l,m,n,o,s,d,w,son.
The total project time is 126.67

The probability that the project would be completed in 5 months i.e. 5*30 = 150 days
The project duration required is 126.67 = Summation of Mean
Summation of Variance = 91.94, Summation of Std. Deviation = Square root of Variance = 9.588

In this case, there is 99.25% chance that the project will be over in 150 days.
At the Hard Rock Café, like many organizations, project management is a key planning tool. Tomasso...
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