The length of zebra pregnancies is normally distributed, with mean μ = 380 and standard deviation...

Question

Question

The length of zebra pregnancies is normally distributed, with mean μ = 380 and standard deviation σ = 10. Find P( x < 375).

Enter your answer as an area under the curve with 4 decimal places.

P( x < 375) =

math Statistics-And-Probability

Answer 1

Answer #1

Solution :

Given that,

mean = = 380

standard deviation = = 10

P(X<375 ) = P[(X- ) / < (375 - 380) / 10]

= P(z <-0.5 )

Using z table

= 0.3085

Answer 2

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