Question

What makes the equilibrium constant, constant? Like, I know that Kc is affected by the conditions...

What makes the equilibrium constant, constant?

Like, I know that Kc is affected by the conditions the reaction takes place in, like temperature. But, if I have four sets of data for the same reaction and each results in the calculation of the same Kc, why is that? Does it have anything to do with the fact that each of the four runs' initial concentrations all sum to 3M? Or is it something else?

0 0
Add a comment Improve this question Transcribed image text
Answer #1

According to law of mass action,

=> Rate of reaction of species active mass of the species (Active mass= Molar concentration without any unit).

=> For a general balanced reversible reaction

=> aA+bB=cC+dD

=> rate of forward and backward reactions are

Rf = Kf [A]a[B]b

and

Rb = Kb[C]c[D]d

Kf & Kb are the rate constant for forward and backward reactions.

At Equilibrium Rf = Rb therefore

Kc = Kf/Kb = [C]c[D]d/[A]a[B]b.......................(1)

From equation number 1 we can say that Kc Does not dependent on the initial concentration of the reactant..

Whether the sum is 3M of it can be any number. Because it is a constant number and generally comes from the Experimental data.

Add a comment
Know the answer?
Add Answer to:
What makes the equilibrium constant, constant? Like, I know that Kc is affected by the conditions...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • At a certain temperature, this reaction establishes an equilibrium with the given equilibrium constant Kc. 3A...

    At a certain temperature, this reaction establishes an equilibrium with the given equilibrium constant Kc. 3A + 2B -><- 4C kc=3.13x10^29 If at this temperature, 2.50 mol of A and 3.70 mol of B are placed in a 1.00L container, what are the concentrations of A, B, C at equilibrium? I know the answer to B and C but system is keep telling me A is wrong The answer I have is [A]=0 <--- wrong [B]=2.033 <--- correct [C}=3.333 <----...

  • I am doing a lab on the determination of the equilibrium constant for the formation of...

    I am doing a lab on the determination of the equilibrium constant for the formation of Fe(SCN)+2. We used a spectrometer to measure the absorption of solutions with a varying initial concentration of Fe+3, but constant concentrations of SCN-. The reaction equation of Fe+3 + SCN- —> Fe(SCN)+2. Along with the SCN- and Fe+3 stock solutions, we also combined them with .3 M HNO3. We then calculated an average molar absorptivity and the equilibrium concentration of Fe(SCN)+2. From that concentration...

  • 1. (6 points) Write the equilibrium constant expression ke for the following reaction: 3 F(b) +...

    1. (6 points) Write the equilibrium constant expression ke for the following reaction: 3 F(b) + Ca(e) = 2 CIF(e) 2. (6 points) Write the equilibrium constant expression Kc for the following reaction: Fe2O3(s) + 3 CO(g) = 2 Fel) + 3 CO2(B) 3. (6 points) Consider the following chemical reaction and the concentrations for each substance: H2O(g) + CH2(g) = CO(g) + 3H2(g) Kc = 4.7 at 1400 K concentration 1.00 M 0.500 M 2.35 M 1.00 M Under...

  • At 390 K, the equilibrium constant, Kc, for the reaction below is 1.8 × 10–3. 1....

    At 390 K, the equilibrium constant, Kc, for the reaction below is 1.8 × 10–3. 1. PCl5 (g) ⇔ PCl3 (g) + Cl2 (g) Assume a quantity of PCl5 (g) is placed in a rigid 10 L vessel and the system is allowed to reach equilibrium at a constant temperature of 390 K. Identify whether each of the following statements is true or false. a) At equilibrium, if the vessel contains 1 mole of PCl5 (g)it must contain 0.0428 mol...

  • i need 2,3,4,5,and 6. 2. (6 Pts) Write the equilibrium expression, Kp, for the reactions in...

    i need 2,3,4,5,and 6. 2. (6 Pts) Write the equilibrium expression, Kp, for the reactions in problem 1. 3. (8 Pts) At 127°C, Kc = 2.6 x 10-5 for the reaction: 2 NH3(g) + N2(g) + 3 H2(g) Calculate Kp at this temperature. 4. (10 Pts) A 1.00-L flask was filled with 2.00 mol gaseous SO2 and 2.00 mol gaseous NO, and heated. After equilibrium was reached, it was found that 1.30 mol gaseous NO was present. Assume that the...

  • Name Equilibrium Constant Lab Prelab assignment 1. Determine the initial concentrations (in molarity) of Fe and...

    Name Equilibrium Constant Lab Prelab assignment 1. Determine the initial concentrations (in molarity) of Fe and SCN" after mixing in each of the 5 beakers in Part I. Then, calculate the [FeSCN2 1 assuming that the reaction goes to completion and that all of the SCN ions react. Show a sample calculation then put your answers in the box below. [FESCN2 Jeg Beaker number [Fe") [SCN' 2 3 4 5 2. In preparing the standard solutions for Part 1, the...

  • I need this code in java. Loops do just what they sound like they should -...

    I need this code in java. Loops do just what they sound like they should - they perform a statement again and again until a condition is fulfilled. For this lab you will be practicing using loops, specifically a for loop. The for loop takes the form of: for(/*variable initialization*/;/*stop condition*/; /*increment*/){ //statements to be done multiple times } Task Write an application that displays every perfect number from 2 through 1,000. A perfect number is one that equals the...

  • 1A) Determine the value of the equilibrium constant, Kgoal, for the reaction CO2(g)⇌C(s)+O2(g),     Kgoal=? by making use...

    1A) Determine the value of the equilibrium constant, Kgoal, for the reaction CO2(g)⇌C(s)+O2(g),     Kgoal=? by making use of the following information: 1. 2CO2(g)+2H2O(l)⇌CH3COOH(l)+2O2(g),       K1 = 5.40×10−16 2. 2H2(g)+O2(g)⇌2H2O(l),       K2 = 1.06×1010 3. CH3COOH(l)⇌2C(s)+2H2(g)+O2(g),       K3 = 2.68×10−9 1B) Determine the equilibrium constant, Kgoal, for the reaction 4PCl5(g)⇌P4(s)+10Cl2(g),    Kgoal=? by making use of the following information: P4(s)+6Cl2(g)⇌4PCl3(g),       K1=2.00×1019 PCl5(g)⇌PCl3(g)+Cl2(g),       K2=1.13×10−2 1C) For a certain reaction, Kc = 8.28×10−5 and kf= 2.12×10−2 M−2⋅s−1 . Calculate the value of the reverse rate constant, kr, given that the reverse...

  • 1) At 298 K, an equilibrium mixture contains P H2=0.958 atm, P I2= 0.877 atm and...

    1) At 298 K, an equilibrium mixture contains P H2=0.958 atm, P I2= 0.877 atm and P HI=0.020 atm. Please try and answer all! You must show all your work to receive credit. Watch sig figs! Consider the reaction: 1) At 298 K, an equilibrium mixture contains P H2-0.958 atm, P ½=0.877 atm, and P HI-0.020 atm. Calculate the value of the equilibrium constant Kp? a) (o, o2) 0.938x o.87? b) And what is the value of the equilibrium constant...

  • Data and Calculations: Determination of the Equilibrium Constant for a Chemical Reaction Method II Volume in...

    Data and Calculations: Determination of the Equilibrium Constant for a Chemical Reaction Method II Volume in mL 2.00 x 103 M Fe(NO) Volume in mL, Depth in mm Volume in ml. 2.00 x 103 M Method I Mixture Unknówn KSCN Water Absorbance Standard FESCNP 4mL 1 5.00 x 10 M 1,00 .227 3mL 2 5,00 202 x 10 M 2,00 90 x 10 M .304 3 5,00 3.00 2mL 955 x 104 M I ImL 4 5.00 4,00 19x 10...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT