What is the 4-decimal area between 1.3 standard deviations below the mean and 2.6 standard deviations above the mean?
The correct answer is .8985
Please show how to get the answer
What is the 4-decimal area between 1.3 standard deviations below the mean and 2.6 standard deviations...
To FOUR DECIMAL PLACES: Determine the area under the standard normal curve that lies to the left of Z = –1.31 to the right of Z = –2.47 between Z = –2.47 and Z = –1.31 between Z = 1.31 and Z = 2.47 Find the z-scores that separate the middle 84% of the standard normal distribution from the area in the tails. Find z0.18 a. Find the Z-score corresponding to the 72nd percentile. In other words, find the Z-score...
Find the area under the standard normal curve within 1.98 standard deviations from the mean. Round to four decimal places.
Give all answers to 4 decimal places. For a standard normal distribution: a) find the probability a score is between the mean and 0.85 standard deviations above the mean? b) find the probability a score is between the mean and 0.85 standard deviations below the mean? c) If the probability that a person scores below a particular value is 0.17, then the probability a person scores above that value equals? d) If the probability that a person scores between...
12
Find the percent of area under a normal curve between the mean and - 1.12 standard deviations from the mean. (Note that positive indicates above the mean, while negative indicates below the mean.) Click here to see page 1 of the table for areas under the standard normal curve Click here to see page 2 of the table for areas under the standard normal curve. %. The percentage of area under a normal curve between the mean and -1.12...
In a normal distribution, a data value located 0.5 standard deviations below the mean has Standard Score: z = In a normal distribution, a data value located 2.4 standard deviations above the mean has Standard Score: z = In a normal distribution, the mean has Standard Score: z =
1)In a standard normal distribution, what proportion of the data set is within 1.75 standard deviations away from the mean? Write your answer in percent and with 2 decimal places. (Answer: 91.99 (with margin: 0.01) please show your work.) 2)A 100-point test was administered to a statistics class. Jack's score was in the 80th percentile. Suppose the statistics class has 120 students and all of them took the test, how many students scored lower than or equal to Jack's score?(Answer:96.0...
1.) Find the area under the standard normal curve between -1.37 and the mean, P(-1.37 < z < 0.00). (Give your answer correct to four decimal places.) 2.) Find the area under the standard normal curve between z = -1.89 and z = 1.21, P(-1.89 < z < 1.21). (Give your answer correct to four decimal places.) 3.) Find the area under the standard normal curve between z = -2.57 and z = 1.51, P(-2.57 < z < 1.51). (Give...
A)What is the z-score of x = 4, if it is 1.9 standard deviations to the left of the mean? (Enter an exact number as an integer, fraction, or decimal.) z = B) What is the z-score of x = 5, if it is 0.166 standard deviations to the left of the mean? (Enter an exact number as an integer, fraction, or decimal.) z = C) Suppose X ~ N(12, 1). What value of x has a z-score of −2.25?...
A manufacturer of bolts has a quality-control policy that requires it to destroy any bolts that are more than 4 standard deviations from the mean. The quality-control engineer knows that the bolts coming off the assembly line have mean length of 15 cm with a standard deviation of 0.05 cm. For what lengths will a bolt be destroyed? Select the correct choice below and fill in the answer box(es) to complete your choice. (Round to one decimal place as neoded.)
Find the number of standard deviations from the mean. Round your answer to two decimal places 12) The annual snowfall in a town has a mean of 33 inches and a standard deviation of 12 inches. Last year there were 69 inches of snow. How many standard deviations from the mean is that? Find the z-score corresponding to the given value and use the z-score to determine whether the value is unusual. Consider a score to be unusual if its...