In an aqueous solution at 223.15 K, the diffusion coefficient of Hemoglobin (r=35 A with dot on top ) is 7.6x10-14 cm2s-1 and for O2 (r=2.0 A with dot on top ) is 1.2x10-12 cm2s-1. The rate constant for binding O2 to Hemoglobin is 4.0x107 M-1s-1. Is this a diffusion-controlled reaction? Find necessary parameter and explain your opinion.
then rate constant k=A as activation energy(Ea) of such processes is zero
diffusion coefficient for hemoglobin radius r1 = 35 A = 3.5 x 10-7 cm
diffusion coefficient of O2 radius r2 = 2 A = 0.2 x 10-7 cm
diffusion coefficient for hemoglobin D1 = 7.6 x 10-14 cm2 s-1
diffusion coefficient for O2 D2 = 1.2 x 10-12 cm2 s-1
NA = Avogadro constant =6.022 x 1023
the equation to calculate the rate constant (kd) is
kd = 4 * pi* NA(r1 + r2)(D1 + D2) M-1 s-1
by incorporating the given values we will get
kd = 4 x 3.14 x 6.022 x 1023 (3.5 x 10-7 cm + 0.2 x 10-7 cm)(7.6 x 10-14 cm 2s-1+ 1.2 x 10-12 cm2 s-1)
kd = 3.57 x 106 cm3 mol-1 s-1
kd = 3.57 x 103 M-1 s-1
since actual rate constant (3.57 x 103 ) is smaller than the diffusion limited rate constant (4 x 107) the reaction is diffusion limited
In an aqueous solution at 223.15 K, the diffusion coefficient of Hemoglobin (r=35 A with dot...
QUESTION 13 The rate In an aqueous solution at 223.15 K, the diffusion coefficient of Hemoglobin (r-35 À ) is 76x1024cm2 and for 02 (-20) )is 1.2x10-12 cm. constant for binding 02 to Hemoglobin is 4.0x10? Is this a diffusion-controlled reaction? Find neceway parameter and explain your opinion. E. BI TTT T Paragraph - Arial (12pt) *DQQETETT. O S.O .S. T. -- M
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Based on the document below,
1. Describe the hypothesis Chaudhuri et al ids attempting to
evaluate; in other words, what is the goal of this paper? Why is he
writing it?
2. Does the data presented in the paper support the hypothesis
stated in the introduction? Explain.
3.According to Chaudhuri, what is the potential role of thew
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