What concentration of NaCHO2 is required to produce a buffer with a pH of 4.25 in a solution that is 1.32M in HCHO2? Ka = 1.8 x 10-4
Ka = 1.8*10^-4
use:
pKa = -log Ka
= -log (1.8*10^-4)
= 3.74
Use:
pH = pKa + log ([CHO2-]/[HCHO2])
4.25 = 3.74 + log ([CHO2-]/1.32)
log ([CHO2-]/1.32) = 0.51
[CHO2-]/1.32 = 10^0.51
[CHO2-]/1.32 = 3.24
[CHO2-] = 4.27 M
Answer: 4.27 M
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